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Question

Which of the following rational number lies between 9.2 and 10.5?

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper (8-Mar-2021) (Shift 2)
The correct answer is
9.55

Rational Number Between 9.2 and 10.5

The question asks to identify a rational number that falls within the range defined by $9.2$ and $10.5$. This means the number must be greater than $9.2$ and less than $10.5$. Mathematically, we are looking for a number $x$ such that:

$9.2 < x < 10.5$

We will examine each option provided to see which one satisfies this condition.

Option Analysis

  • Option 1: $10.67$
    • Check: Is $9.2 < 10.67 < 10.5$?
    • Result: No, because $10.67$ is greater than $10.5$.
  • Option 2: $9.08$
    • Check: Is $9.2 < 9.08 < 10.5$?
    • Result: No, because $9.08$ is less than $9.2$.
  • Option 3: $9.15$
    • Check: Is $9.2 < 9.15 < 10.5$?
    • Result: No, because $9.15$ is less than $9.2$.
  • Option 4: $9.55$
    • Check: Is $9.2 < 9.55 < 10.5$?
    • Result: Yes, because $9.55$ is greater than $9.2$ and less than $10.5$.

Conclusion

Based on the analysis, the number $9.55$ is the only option that lies strictly between $9.2$ and $10.5$.

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Important Questions from Rational or Irrational Numbers

  1. If \(\sqrt{1+\frac{\sqrt{3}}{2}}- \sqrt{1-\frac{\sqrt{3}}{2}}= c\) , then the value of c is:

  2. If \(\frac{\sqrt{38-5\sqrt{3} } }{\sqrt{26+7\sqrt{3} } }= \frac{a+b\sqrt{3} }{23} \) , b > 0, then the value of (b – a) is:

  3. If \( \frac{5}{4{\sqrt 2 }} + \frac{{3 + 2\sqrt 2 }}{{3 - 2\sqrt 2 }} - \frac{{3 - 2\sqrt 2 }}{{3 + 2\sqrt 2 }} = a + b\sqrt 2 \) , then what is the value of (3a + 4b)?

  4. If \(\frac {8 + 2\sqrt 3}{3\sqrt 3 + 5} = a\sqrt 3 - b,\)  then the value of a + b is equal to:

  5. If \(\frac{\sqrt{26-7\sqrt{3} } }{\sqrt{14+5\sqrt{3} } } = \frac{b+a\sqrt{3} }{11}\) , b > 0, then what is the value of  \(\sqrt{(b-a)} \)  ?

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