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Question

The arrangement of rational numbers $-\frac{7}{10}, \frac{5}{-8}, \frac{2}{-3}$ in ascending order is:

This question was previously asked in
RRB NTPC 2019 CBT 1 Question Paper (8-Mar-2021) (Shift 2)
The correct answer is
$-\frac{7}{10}, \frac{2}{-3}, \frac{5}{-8}$

To arrange the rational numbers $-\frac{7}{10}, \frac{5}{-8}, \frac{2}{-3}$ in ascending order, we first express them with positive denominators and then find a common denominator.

Standardizing Rational Numbers

Rewrite the given fractions to have positive denominators:

  • $-\frac{7}{10}$ remains $-\frac{7}{10}$
  • $\frac{5}{-8}$ becomes $-\frac{5}{8}$
  • $\frac{2}{-3}$ becomes $-\frac{2}{3}$

The numbers to order are now: $-\frac{7}{10}, -\frac{5}{8}, -\frac{2}{3}$.

Finding Common Denominator

The denominators are 10, 8, and 3. We find the Least Common Multiple (LCM) of these numbers.

  • Prime factorization of 10 = $2 \times 5$
  • Prime factorization of 8 = $2^3$
  • Prime factorization of 3 = $3$
  • LCM(10, 8, 3) = $2^3 \times 3 \times 5 = 8 \times 3 \times 5 = 120$.

The common denominator is 120.

Converting to Equivalent Fractions

Convert each fraction to an equivalent fraction with a denominator of 120:

  • $-\frac{7}{10} = -\frac{7 \times 12}{10 \times 12} = -\frac{84}{120}$
  • $-\frac{5}{8} = -\frac{5 \times 15}{8 \times 15} = -\frac{75}{120}$
  • $-\frac{2}{3} = -\frac{2 \times 40}{3 \times 40} = -\frac{80}{120}$

Comparing and Ordering

We need to arrange the fractions $-\frac{84}{120}, -\frac{75}{120}, -\frac{80}{120}$ in ascending order. Since all numbers are negative, the number with the largest numerator (in absolute value) is the smallest.

Comparing the numerators: -84, -75, -80.

The ascending order of the numerators is -84, -80, -75.

Therefore, the ascending order of the fractions is:

$-\frac{84}{120} < -\frac{80}{120} < -\frac{75}{120}$

Final Ascending Order

Convert the ordered fractions back to their original form:

  • $-\frac{84}{120}$ corresponds to $-\frac{7}{10}$
  • $-\frac{80}{120}$ corresponds to $-\frac{2}{3}$ (or $\frac{2}{-3}$)
  • $-\frac{75}{120}$ corresponds to $-\frac{5}{8}$ (or $\frac{5}{-8}$)

The rational numbers in ascending order are $-\frac{7}{10}, \frac{2}{-3}, \frac{5}{-8}$.

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Important Questions from Rational or Irrational Numbers

  1. If \(\sqrt{1+\frac{\sqrt{3}}{2}}- \sqrt{1-\frac{\sqrt{3}}{2}}= c\) , then the value of c is:

  2. If \(\frac{\sqrt{38-5\sqrt{3} } }{\sqrt{26+7\sqrt{3} } }= \frac{a+b\sqrt{3} }{23} \) , b > 0, then the value of (b – a) is:

  3. If \( \frac{5}{4{\sqrt 2 }} + \frac{{3 + 2\sqrt 2 }}{{3 - 2\sqrt 2 }} - \frac{{3 - 2\sqrt 2 }}{{3 + 2\sqrt 2 }} = a + b\sqrt 2 \) , then what is the value of (3a + 4b)?

  4. If \(\frac {8 + 2\sqrt 3}{3\sqrt 3 + 5} = a\sqrt 3 - b,\)  then the value of a + b is equal to:

  5. If \(\frac{\sqrt{26-7\sqrt{3} } }{\sqrt{14+5\sqrt{3} } } = \frac{b+a\sqrt{3} }{11}\) , b > 0, then what is the value of  \(\sqrt{(b-a)} \)  ?

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