Read the following and answer the questions that follow. Use the following schema of the academic institution relational database: student (rollno, name, degree, year, sex, deptno, advisor) department (deptid, name, hod, phone) professor (empid, name, sex, startyear, deptno, phone) course (courseid, cname, credits, deptno) enrollment (rollno, courseid, sem, year, grade) teaching (empid, courseid, sem, year, classroom) prerequisite (precourseid, courseid) deptno is foreign key in the student, professor and course relations referring to deptid of department relation; advisor is a foreign key in the student relation referring to empid of professor relation; hod is a foreign key in the department relation referring to empid of professor relation; rollno is a foreign key in the enrollment relation referring to rollno of student relation; courseid is a foreign key in the enrollment, teaching relations referring to courseid of course relation; empid is a foreign key of the teaching relation referring to empid of professor relation; precourseid and courseid are foreign keys in the prerequisite relation referring to courseid of the course relation;
Which of the following queries would compute, for each department, the total credits of all the courses offered by the department?
select deptid, name, sum(credits) as totalcredits
from department, course
where deptid=deptno
group by deptid, name;
To get one total per department, the department and course rows must be joined on the foreign key (deptid = deptno), grouped per department, and the credits added with SUM. Row-level join conditions belong in WHERE; HAVING filters groups after aggregation.
Step 1 — FROM department, course with WHERE deptid=deptno pairs each course with the department that offers it.
Step 2 — GROUP BY deptid, name forms one group per department (name is functionally dependent on deptid and is listed so that it may appear in SELECT).
Step 3 — sum(credits) adds the credits of all courses in each group, giving totalcredits per department.
The count(credits) version returns the number of courses, not the total of their credits. The version without GROUP BY mixes the non-aggregated columns deptid and name with sum(credits), which is invalid (or, at best, one row for the whole join). The version with HAVING deptid=deptno groups the unfiltered Cartesian product and then tests deptno, a column that is neither grouped nor aggregated, so it is invalid and does not restrict rows before summing.
select deptid, name, sum(credits) as totalcredits from department, course where deptid=deptno group by deptid, name; option is correct.
Similar Questions
Consider the following three SQL queries (Assume the data in the people table) :
(a) Select Name from people where Age>21;
(b) Select Name from people where Height>180;
(c) Select Name from people where (Age>21) or (Height>180);
If the SQL queries (a) and (b) above, return 10 rows and 7 rows in the result set respectively, then what is one possible number of rows returned by the SQL query (c) ?
Suppose ORACLE relation R(A, B) currently has tuples {(1, 2), (1, 3), (3, 4)} and relation S(B, C) currently has {(2, 5), (4, 6), (7, 8)}. Consider the following two SQL queries SQ1 and SQ2 :
SQ1 : Select *
From R Full Join S
On R.B = S.B;
SQ2 : Select *
From R Inner Join S
On R.B = S.B;
The numbers of tuples in the result of the SQL query SQ1 and the SQL query SQ2 are given by :
Consider a “CUSTOMERS” database table having a column “CITY” filled with all the names of Indian cities (in capital letters). The SQL statement that finds all cities that have “GAR” somewhere in its name, is :
The STUDENT information in a university stored in the relation STUDENT (Name, SEX, Marks, DEPT_Name)
Consider the following SQL Query SELECT DEPT_Name from STUDENT where SEX = ‘M’ group by DEPT_Name having avg (Marks)>SELECT avg (Marks) from STUDENT. It Returns the Name of the Department for which :
An Assertion is a predicate expressing a condition we wish database to always satisfy. The correct syntax for Assertion is :
Match the following :
List - I List - II a. DDL i. LOCK TABLE b. DML ii. COMMIT c. TCL iii. Natural Difference d. BINARY Operation iv. REVOKE Codes :
Given query:
select s.rollno, s.name
from student s
where EXISTS (select c.courseid from course c Where c.deptno=5 and
EXISTS (select e.* from enrollemnt e
where e.courseid = c.courseid and
e.rollno = s.rollno));
Which one of the following statements is correct with respect to the given query?
Which of the following queries would retrieve the dept id and name of all the departments that are such that the total of the credits of all the offered courses by the department is strictly greater than 40?
Given query: select s.rollno from students where s.sex = ALL (select f.sex from professor f where f.empid = s.advisor)
Consider the following statements about the given query that retrieves the set of all students whose gender is same as the gender of their advisor:
S1. It has a correlated subquery
S2. It has an uncorrelated subquery
S3. If we replace ALL by ANY in the above query, its result will be different
S4. If we replace ALL by ANY in the above query, its result will be same.
Identify all the statement that are TRUE:
Which of the following queries would retrieve the roll number and names of students who have enrolled for all the prerequisite courses of the course number 324?
Important Questions from SQL
Match the following -
List I List II (a) DDL (i) LOCK TABLE (b) DML (ii) COMMIT (c) TCL (iii) Natural Difference (d) Binary operation (iv) REVOKE Which of the following is NOT a Structured Query Language Data type?
Consider a table Employee(EmpID, TeamID), where the column EmpID (ID of an employee) is the primary key. The column TeamID denotes the team ID of the team of which the employee is a member. TeamID is a NOT NULL column.
We want to display the size of the team (denoted as TeamSize) in which each employee is a member by using SQL. As an example, the desired output for the given Employee table is also shown in tabular form.Which of the following is/are correct?
Employee
EmpID TeamID 1 8 2 8 3 8 4 7 5 7 6 9
Output
EmpID TeamSize 1 3 2 3 3 3 4 2 5 2 6 1 Let Account be a relation as shown.
Account
AccNo Balance A1 5000 A2 5000 A3 10000 A4 15000 A5 18000 Consider the given SQL query.
SELECT AccNo FROM Account AS A
WHERE (SELECT COUNT(*) FROM Account AS B
WHERE A.Balance < B.Balance) >= (SELECT COUNT(*)
FROM Account AS C WHERE A.Balance > C.Balance)
The number of rows returned by the SQL query is __________ . (Answer in integer)
Consider the following two tables named Raider and Team in a relational database maintained by a Kabaddi league. The attribute ID in table Team references the primary key of the Raider table, ID.
Raider ID Name Raids RaidPoints 1 Arjun 200 250 2 Ankush 190 219 3 Sunil 150 200 4 Reza 150 190 5 Pratham 175 220 6 Gopal 193 215 Team City ID BidPoints Jaipur 2 200 Patna 3 195 Hyderabad 5 175 Jaipur 1 250 Patna 4 200 Jaipur 6 200 The SQL query described below is executed on this database:
SELECT *
FROM Raider, Team
WHERE Raider.ID=Team.ID AND City="Jaipur" AND
RaidPoints > 200;
The number of rows returned by this query is ________.
