Which of the following interchanges of signs would make the given equation correct? 100 + 100 × 50 - 2 ÷ 3 = 51
+ and ÷
The problem asks us to find which interchange of two mathematical signs from the given equation will make the equation correct. The initial equation is:
\(100 + 100 \times 50 - 2 \div 3 = 51\)
Let's first evaluate the original equation using the order of operations (BODMAS/PEMDAS - Brackets, Orders, Division/Multiplication, Addition/Subtraction):
So the equation becomes approximately: \(100 + 5000 - 0.67 = 5100 - 0.67 = 5099.33\)
Clearly, \(5099.33\) is not equal to \(51\), so the original equation is incorrect. We need to test the given options by swapping the specified signs and re-evaluating the equation.
If we interchange the '+' and '÷' signs, the equation becomes:
\(100 \div 100 \times 50 - 2 + 3\)
Now, let's evaluate this new equation using BODMAS:
The equation is now: \(1 \times 50 - 2 + 3\)
The equation is now: \(50 - 2 + 3\)
So, the equation becomes \(51\). This matches the right side of the original target equation.
\(100 \div 100 \times 50 - 2 + 3 = 51\)
Let's quickly look at the other options to see if they yield 51.
Equation becomes: \(100 - 100 \times 50 + 2 \div 3\)
Evaluation: \(100 - (100 \times 50) + (2 \div 3) = 100 - 5000 + 0.67 \approx -4899.33\). This is not 51.
Equation becomes: \(100 + 100 - 50 \times 2 \div 3\)
Evaluation: \(100 + 100 - (50 \times 2) \div 3 = 200 - 100 \div 3 \approx 200 - 33.33 \approx 166.67\). This is not 51.
Equation becomes: \(100 + 100 \div 50 - 2 \times 3\)
Evaluation: \(100 + (100 \div 50) - (2 \times 3) = 100 + 2 - 6 = 102 - 6 = 96\). This is not 51.
Based on the evaluation of each option, only interchanging the '+' and '÷' signs makes the given equation correct.
| Order | Mnemonic | Operation |
|---|---|---|
| 1 | B / P | Brackets / Parentheses |
| 2 | O / E | Orders / Exponents (powers, square roots) |
| 3 | D M | Division and Multiplication (from left to right) |
| 4 | A S | Addition and Subtraction (from left to right) |
Problems involving interchanging signs or numbers in equations are common in reasoning and quantitative aptitude tests. Here are some tips for solving them:
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