Which of the following interchanges of signs would make the given equation correct? 100 + 100 × 50 - 2 ÷ 3 = 51
+ and ÷
The problem asks us to find which interchange of two mathematical signs from the given equation will make the equation correct. The initial equation is:
\(100 + 100 \times 50 - 2 \div 3 = 51\)
Let's first evaluate the original equation using the order of operations (BODMAS/PEMDAS - Brackets, Orders, Division/Multiplication, Addition/Subtraction):
So the equation becomes approximately: \(100 + 5000 - 0.67 = 5100 - 0.67 = 5099.33\)
Clearly, \(5099.33\) is not equal to \(51\), so the original equation is incorrect. We need to test the given options by swapping the specified signs and re-evaluating the equation.
If we interchange the '+' and '÷' signs, the equation becomes:
\(100 \div 100 \times 50 - 2 + 3\)
Now, let's evaluate this new equation using BODMAS:
The equation is now: \(1 \times 50 - 2 + 3\)
The equation is now: \(50 - 2 + 3\)
So, the equation becomes \(51\). This matches the right side of the original target equation.
\(100 \div 100 \times 50 - 2 + 3 = 51\)
Let's quickly look at the other options to see if they yield 51.
Equation becomes: \(100 - 100 \times 50 + 2 \div 3\)
Evaluation: \(100 - (100 \times 50) + (2 \div 3) = 100 - 5000 + 0.67 \approx -4899.33\). This is not 51.
Equation becomes: \(100 + 100 - 50 \times 2 \div 3\)
Evaluation: \(100 + 100 - (50 \times 2) \div 3 = 200 - 100 \div 3 \approx 200 - 33.33 \approx 166.67\). This is not 51.
Equation becomes: \(100 + 100 \div 50 - 2 \times 3\)
Evaluation: \(100 + (100 \div 50) - (2 \times 3) = 100 + 2 - 6 = 102 - 6 = 96\). This is not 51.
Based on the evaluation of each option, only interchanging the '+' and '÷' signs makes the given equation correct.
| Order | Mnemonic | Operation |
|---|---|---|
| 1 | B / P | Brackets / Parentheses |
| 2 | O / E | Orders / Exponents (powers, square roots) |
| 3 | D M | Division and Multiplication (from left to right) |
| 4 | A S | Addition and Subtraction (from left to right) |
Problems involving interchanging signs or numbers in equations are common in reasoning and quantitative aptitude tests. Here are some tips for solving them:
Read the given statements and conclusions carefully. You have to take the given statements to be true even if they seem to be at variance from commonly known facts. You have to decide which conclusion/s logically follow/s from the given statements.
Statements:
All beaches are sand.
Some deserts are sand.
All mountains are rocky.
Conclusions:
(I) At least some beaches are desert.
(II) At least some sands are rocky.
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