1+5+7+9+11+13+15+17+21+23
This question focuses on a well-known mathematical property related to the sum of consecutive odd numbers and how it relates to squares. A fundamental rule in arithmetic progression states that the sum of the first n odd natural numbers is always equal to the square of n . Therefore, the correct answer is 1+5+7+9+11+13+15+17+21+23.
| (i) Sindhia | (a) Indore |
| (ii) Holkar | (b) Nagpur |
| (iii) Gaekwad | (c) Ujjain |
| (iv) Bhonsle | (d) Baroda |
What will be the value of following equation?
\( \frac{2.4 \times 0.72 \times 4.5}{0.18 \times 0.06 \times 0.9}\times 3 \)
Simplify: \( {9^{-2} \times 3^{5} \times (5^{-2}) ^{3}} / (3^{-3}) ^{4} \times 5^{4} \)
(Note: Question or options appear to be incorrect as the calculated result does not match any option.)
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