When we pass an array as an argument to a function, what actually gets passed ?
Base address of the array
In C, an array name used as an argument decays to a pointer to its first element.
So the function receives the base address of the array, that is, the address of element 0, and works on the original elements through it.
The element values are not copied, and the size is not passed automatically.
Hence, Base address of the array.
A three dimensional array in ‘C’ is declared as int A[x][y][z]. Here, the address of an item at the location A[p][q][r] can be computed as follows (where w is the word length of an integer) :
Given
int arr[3][4][2]= {{{2,4},{7,8},{3,4},{5,6}},{{7,6},{3,4},{5,3},{2,3}},{{8.9},{7,2},{3,4},{5,1}}};
Which one of the following can be used to refer to element 1 in the above 3-d array?
Which of the following is true for computation time in insertion, deletion and finding maximum and minimum element in a sorted array ?
Consider an array A[20, 10], assume 4 words per memory cell and the base address of array A is 100. What is the address of A[11, 5] ? Assume row major storage.
When an array is passed as parameter to a function, which of the following statements is correct ?
Consider the following C program segment.
#include <stdio.h>
int main()
{
char s1[7] = "1234";
char *p;
p = s1 + 2;
*p = '0';
printf("%s", s1);
return 0;
}
#include <stdio.h>
void foo(int *p, int x){
*p = x;
}
int main(){
int *z;
int a = 20, b = 25;
z = &a;
foo(z, b);
printf("%d", a);
return 0;
}
What is the output the given C language code snippet?
#include<stdio.h>
int main()
{
int x[] = {10,20,30};
int *p = x;
p++;
printf("%d",*p);
return 0;
}
Which of the following expression will delete the entire array pointed to by q?