Consider an array A[20, 10], assume 4 words per memory cell and the base address of array A is 100. What is the address of A[11, 5] ? Assume row major storage.
560
In row major order, the address of element A[i, j] in an array with n columns is \(\text{Base} + (i \times n + j) \times w\), where w is the size of one element and indices start from 0.
Here the array has 20 rows and n = 10 columns, the base address is 100 and w = 4 words.
Number of elements before A[11, 5] = \(11 \times 10 + 5 = 115\).
Address = \(100 + 115 \times 4 = 100 + 460 = 560\).
Hence, the answer is 560.
Similar Questions
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Given
int arr[3][4][2]= {{{2,4},{7,8},{3,4},{5,6}},{{7,6},{3,4},{5,3},{2,3}},{{8.9},{7,2},{3,4},{5,1}}};
Which one of the following can be used to refer to element 1 in the above 3-d array?
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Important Questions from Array
Consider the following C program segment.
#include <stdio.h>
int main()
{
char s1[7] = "1234";
char *p;p = s1 + 2;
*p = '0';printf("%s", s1);
return 0;
What will be printed by the program?
}#include <stdio.h> void foo(int *p, int x){ *p = x; } int main(){ int *z; int a = 20, b = 25; z = &a; foo(z, b); printf("%d", a); return 0; }The output of the given C program is __________. (Answer in integer)- Consider an array $A$ of integers of size $n$. The indices of $A$ run from 1 to $n$. An algorithm is to be designed to check whether $A$ satisfies the condition given below.
$\forall i,j \in \{1, \dots, n-1\}$ such that $i > j$, $(A[i + 1] - A[i]) > (A[j + 1] - A[j])$
Which one of the following gives the worst case time complexity of the fastest algorithm that can be designed for the problem? What is the output the given C language code snippet?
#include<stdio.h>
int main()
{
int x[] = {10,20,30};
int *p = x;
p++;
printf("%d",*p);
return 0;
}
Which of the following expression will delete the entire array pointed to by q?
