When the speed of a truck is increased by 20%, it takes 25 minutes less to cover the same distance. What is the time (in hours) taken to cover twice the distance at its actual speed?
5
The correct answer is 5.
T_{\text{new}} = \frac{1}{1.2} T We also know T_{\text{new}} = T - 25. So: T - 25 = \frac{1}{1.2} T T - \frac{1}{1.2} T = 25 T \left(1 - \frac{1}{1.2}\right) = 25 T \left(1 - \frac{10}{12}\right) = 25 T \left(1 - \frac{5}{6}\right) = 25 T \left(\frac{6 - 5}{6}\right) = 25 T \left(\frac{1}{6}\right) = 25 T = 25 \times 6 = 150 minutes This confirms our earlier calculation for the original time T.
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