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Question

A truck, 1575 metres long is running at a speed of 109 km/hr. How many seconds will it take to cross a 1475 metres long train running in the same direction at a speed of 79 km/hr?

The correct answer is
366

Solving Truck and Train Crossing Time Problem

This problem involves calculating the time it takes for a faster-moving object (truck) to completely pass a slower-moving object (train) when both are moving in the same direction.

Key Concepts: Relative Speed and Total Distance

  • Relative Speed: When two objects move in the same direction, their relative speed is the difference between their individual speeds. This is the speed at which the faster object gains on the slower object.
  • Total Distance: For the truck to completely cross the train, the effective distance to be covered is the sum of the length of the truck and the length of the train.

Given Information

  • Length of Truck ($L_T$): 1575 metres
  • Speed of Truck ($S_T$): 109 km/hr
  • Length of Train ($L_{Tr}$): 1475 metres
  • Speed of Train ($S_{Tr}$): 79 km/hr
  • Direction: Same

Step-by-Step Calculation

  1. Calculate Relative Speed:

    Since they are moving in the same direction, the relative speed ($S_{Rel}$) is:

    \( S_{Rel} = S_T - S_{Tr} \)

    \( S_{Rel} = 109 \text{ km/hr} - 79 \text{ km/hr} = 30 \text{ km/hr} \)

  2. Convert Speed to Metres per Second (m/s):

    To find the time in seconds, convert the relative speed from km/hr to m/s using the conversion factor \(\frac{5}{18}\).

    \( S_{Rel} (\text{m/s}) = 30 \times \frac{5}{18} = \frac{150}{18} = \frac{25}{3} \text{ m/s} \)

  3. Calculate Total Distance:

    The total distance ($D_{Total}$) the truck needs to cover relative to the train is the sum of their lengths.

    \( D_{Total} = L_T + L_{Tr} \)

    \( D_{Total} = 1575 \text{ m} + 1475 \text{ m} = 3050 \text{ m} \)

  4. Calculate Time to Cross:

    Time ($T$) is calculated using the formula: Time = Total Distance / Relative Speed.

    \( T = \frac{D_{Total}}{S_{Rel} (\text{m/s})} \)

    \( T = \frac{3050 \text{ m}}{\frac{25}{3} \text{ m/s}} \)

    \( T = 3050 \times \frac{3}{25} \text{ s} \)

    \( T = 122 \times 3 \text{ s} \)

    \( T = 366 \text{ s} \)

Therefore, the truck will take 366 seconds to cross the train.

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Important Questions from Relative Speed

  1. In a circular race of 2500 m, a man and a woman start from a point towards opposite directions with speeds of 37 km/h and 35 km/h, respectively. After how much time from the start of the race will they meet for the first time?

  2. X and Yrun a 3 km race along a circular course of length 300 m. Their speeds are in the ratio 3 : 2. If they start together in the same direction, how many times would the first one pass the other (the start-off is not counted as passing)?
  3. A train of length 600 meters passes another train of length 1000 meters moving in the opposite direction in 96 seconds. If the speed of both the trains is the same, then what is the speed of each train?

  4. A train, running at a speed of 36 kmph, takes 60 seconds to cross an electric pole. How much time it will take to cross a platform of length 250 meter?

  5. A truck covered a distance of 780 km in 12 hours. What distance would a car cover in 11 hours travelling at a speed which is seven kmph more than that of the truck?

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