This problem involves calculating the time it takes for a faster-moving object (truck) to completely pass a slower-moving object (train) when both are moving in the same direction.
Since they are moving in the same direction, the relative speed ($S_{Rel}$) is:
\( S_{Rel} = S_T - S_{Tr} \)
\( S_{Rel} = 109 \text{ km/hr} - 79 \text{ km/hr} = 30 \text{ km/hr} \)
To find the time in seconds, convert the relative speed from km/hr to m/s using the conversion factor \(\frac{5}{18}\).
\( S_{Rel} (\text{m/s}) = 30 \times \frac{5}{18} = \frac{150}{18} = \frac{25}{3} \text{ m/s} \)
The total distance ($D_{Total}$) the truck needs to cover relative to the train is the sum of their lengths.
\( D_{Total} = L_T + L_{Tr} \)
\( D_{Total} = 1575 \text{ m} + 1475 \text{ m} = 3050 \text{ m} \)
Time ($T$) is calculated using the formula: Time = Total Distance / Relative Speed.
\( T = \frac{D_{Total}}{S_{Rel} (\text{m/s})} \)
\( T = \frac{3050 \text{ m}}{\frac{25}{3} \text{ m/s}} \)
\( T = 3050 \times \frac{3}{25} \text{ s} \)
\( T = 122 \times 3 \text{ s} \)
\( T = 366 \text{ s} \)
Therefore, the truck will take 366 seconds to cross the train.
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A truck covered a distance of 780 km in 12 hours. What distance would a car cover in 11 hours travelling at a speed which is seven kmph more than that of the truck?