The problem asks for the time it takes for a truck to cross a train moving in the same direction. We need to use the concept of relative speed.
The truck's speed ($S_T$) is 112 km/hr and the train's speed ($S_{Tr}$) is 82 km/hr. Since they are moving in the same direction, the relative speed ($S_{rel}$) is the difference between their speeds:
$ S_{rel} = S_T - S_{Tr} $
$ S_{rel} = 112 \text{ km/hr} - 82 \text{ km/hr} = 30 \text{ km/hr} $
To find the time in seconds, we need to convert the relative speed from km/hr to m/s. The conversion factor is:
$ 1 \text{ km/hr} = \frac{5}{18} \text{ m/s} $
Therefore, the relative speed in m/s is:
$ S_{rel} = 30 \times \frac{5}{18} \text{ m/s} = \frac{150}{18} \text{ m/s} = \frac{25}{3} \text{ m/s} $
The total distance ($D$) the truck must cover to completely cross the train is the sum of the truck's length ($L_T$) and the train's length ($L_{Tr}$).
Truck length ($L_T$) = 1600 metres
Train length ($L_{Tr}$) = 1500 metres
$ D = L_T + L_{Tr} $
$ D = 1600 \text{ m} + 1500 \text{ m} = 3100 \text{ m} $
The time ($T$) taken to cross is calculated using the formula:
$ T = \frac{\text{Total Distance}}{\text{Relative Speed}} $
$ T = \frac{D}{S_{rel}} $
$ T = \frac{3100 \text{ m}}{\frac{25}{3} \text{ m/s}} $
$ T = 3100 \times \frac{3}{25} \text{ seconds} $
$ T = \frac{9300}{25} \text{ seconds} $
$ T = 372 \text{ seconds} $
Thus, it will take the truck 372 seconds to cross the train.
Consider an equilateral triangle ABC as given in the following diagram :

Two people start at the same time from points A and B with speeds 30 km per hour and 20 km per hour respectively, and move on the sides of the triangle in the clockwise direction. They meet each other for the first time at