This problem requires calculating the time it takes for two individuals moving towards each other to meet. The key concept used is relative speed.
When two objects move towards each other, their speeds combine. This combined speed, known as relative speed, determines how quickly the distance between them decreases.
Relative speed, $S_{rel} = S_1 + S_2$
$S_{rel} = 10 \text{ km/hr} + 14 \text{ km/hr} = 24 \text{ km/hr}$
The time required for the friends to meet is calculated by dividing the total initial distance by their relative speed.
Time, $T = \frac{D}{S_{rel}}$
$T = \frac{10 \text{ km}}{24 \text{ km/hr}} = \frac{10}{24}$ hours
To express the meeting time in minutes, convert the time from hours by multiplying by 60.
$T_{\text{minutes}} = \frac{10}{24} \times 60$ minutes
$T_{\text{minutes}} = \frac{600}{24}$ minutes
$T_{\text{minutes}} = 25$ minutes
The calculation indicates the friends will meet in 25 minutes. Option C is 28 minutes.
Consider an equilateral triangle ABC as given in the following diagram :

Two people start at the same time from points A and B with speeds 30 km per hour and 20 km per hour respectively, and move on the sides of the triangle in the clockwise direction. They meet each other for the first time at