A person travelled from a place Z to P at an average speed of 130 km/h. He travelled the first 75% of the distance in two-third of the time and the rest at a constant speed of X km/h. The value of 2X is:
195
The correct answer is 195.
Let's verify this relationship: \text{Average Speed} = \frac{S_1 (\frac{2}{3}T) + X (\frac{1}{3}T)}{T} 130 = \frac{T(\frac{2}{3}S_1 + \frac{1}{3}X)}{T} 130 = \frac{2}{3}S_1 + \frac{1}{3}X Substitute S_1 = 146.25 and X = 97.5: 130 = \frac{2}{3}(146.25) + \frac{1}{3}(97.5) 130 = \frac{292.5}{3} + \frac{97.5}{3} 130 = 97.5 + 32.5 130 = 130 This confirms our calculated values for S_1 and X are consistent with the total average speed and the time distribution.
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