The problem asks us to find the principal sum (P) that yields a simple interest (SI) of ₹480 over a period of 2 years (T) at an annual interest rate (R) of 10%.
The formula for calculating simple interest is:
\( SI = \frac{P \times R \times T}{100} \)
To find the principal sum (P), we can rearrange the formula:
\( P = \frac{SI \times 100}{R \times T} \)
Now, substitute the given values into the rearranged formula:
\( P = \frac{480 \times 100}{10 \times 2} \)
First, calculate the numerator and the denominator:
Numerator = \(480 \times 100 = 48000\)
Denominator = \(10 \times 2 = 20\)
Now, perform the division:
\( P = \frac{48000}{20} \)
\( P = 2400 \)
Therefore, the principal sum required is ₹2400.
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