The problem asks us to find the principal sum (P) that yields a simple interest (SI) of ₹480 over a period of 2 years (T) at an annual interest rate (R) of 10%.
The formula for calculating simple interest is:
\( SI = \frac{P \times R \times T}{100} \)
To find the principal sum (P), we can rearrange the formula:
\( P = \frac{SI \times 100}{R \times T} \)
Now, substitute the given values into the rearranged formula:
\( P = \frac{480 \times 100}{10 \times 2} \)
First, calculate the numerator and the denominator:
Numerator = \(480 \times 100 = 48000\)
Denominator = \(10 \times 2 = 20\)
Now, perform the division:
\( P = \frac{48000}{20} \)
\( P = 2400 \)
Therefore, the principal sum required is ₹2400.
The simple interest on ₹1,280 at 5% p.a. in 3 years is:
A invests ₹8000 and B invests ₹11000 at the same rate of simple interest per annum. If at the end of 3 years, B gets ₹720 more interest than A, then find the rate of simple interest per annum.
A sum of money lent on simple interest becomes \(7\over5\) of itself in 4 years. Find the rate of interest per annum.
What sum will earn a simple interest of ₹480 in 3 years at a 16% per year rate of interest?
Find the simple interest of ₹3,000 as a sum borrowed at a 4% per year rate of interest for 5 years.
How much time will it take for an amount of Rs. 450 to yield Rs. 81 as interest at 4.5% per annum of simple interest ?
Nirav and Mehul borrowed Rs.4000 and Rs.5000 respectively for 2.5 years at the rate of x% per annum. Mehul paid Rs 125 more interest than Nirav. Find x.
If the interest on a sum of Rs.1200 is more than the interest on Rs.1000 by Rs.120 in three years, then what is the rate of interest per annum?.
The difference between the simple interest received from two banks on Rs. 500 for two years is Rs. 2.50. What is the difference between their rates?
A sum of Rs.1200 becomes Rs.1560 at a rate of simple interest in 3 years. In how many years will the sum of Rs.800 amount to Rs.1120 at the same rate of simple interest?