What is the whole surface area of a cone of base radius 6 cm and height 8 cm?
301.71 cm2
To find the whole surface area of a cone, we need to calculate the sum of the area of its circular base and its lateral surface area. The formula for the total surface area (TSA) of a cone is given by:
TSA = Area of Base + Lateral Surface Area
The area of the circular base is $\pi r^2$, where $r$ is the base radius.
The lateral surface area is $\pi r l$, where $r$ is the base radius and $l$ is the slant height of the cone.
So, the total surface area formula is:
\( \text{TSA} = \pi r^2 + \pi r l = \pi r (r + l) \)
We are given the base radius ($r$) and the height ($h$) of the cone, but not the slant height ($l$). The radius, height, and slant height of a cone form a right-angled triangle, with the slant height being the hypotenuse. We can use the Pythagorean theorem to find the slant height:
\( l^2 = r^2 + h^2 \)
\( l = \sqrt{r^2 + h^2} \)
Given:
Let's calculate the slant height:
\( l = \sqrt{(6 \text{ cm})^2 + (8 \text{ cm})^2} \)
\( l = \sqrt{36 \text{ cm}^2 + 64 \text{ cm}^2} \)
\( l = \sqrt{100 \text{ cm}^2} \)
\( l = 10 \text{ cm} \)
So, the slant height of the cone is 10 cm.
Now that we have the radius ($r = 6$ cm) and the slant height ($l = 10$ cm), we can calculate the total surface area using the formula:
\( \text{TSA} = \pi r (r + l) \)
Substitute the values:
\( \text{TSA} = \pi \times 6 \text{ cm} \times (6 \text{ cm} + 10 \text{ cm}) \)
\( \text{TSA} = \pi \times 6 \text{ cm} \times (16 \text{ cm}) \)
\( \text{TSA} = 96\pi \text{ cm}^2 \)
To get a numerical value, we use an approximate value for $\pi$. Using $\pi \approx 3.14159$:
\( \text{TSA} \approx 96 \times 3.14159 \text{ cm}^2 \)
\( \text{TSA} \approx 301.59264 \text{ cm}^2 \)
Using $\pi \approx \frac{22}{7} \approx 3.14286$:
\( \text{TSA} \approx 96 \times \frac{22}{7} \text{ cm}^2 \)
\( \text{TSA} \approx \frac{2112}{7} \text{ cm}^2 \)
\( \text{TSA} \approx 301.714... \text{ cm}^2 \)
Comparing our calculated value to the given options, the value calculated using $\pi \approx \frac{22}{7}$ is closest to one of the options.
Let's compare our calculated area ($301.714... \text{ cm}^2$) with the options provided:
The calculated total surface area of approximately 301.71 cm\(^2\) matches Option 3.
| Component | Formula | Calculation |
|---|---|---|
| Base Area | \(\pi r^2\) | \(\pi (6)^2 = 36\pi\) cm\(^2\) |
| Slant Height (l) | \(\sqrt{r^2 + h^2}\) | \(\sqrt{6^2 + 8^2} = \sqrt{36 + 64} = \sqrt{100} = 10\) cm |
| Lateral Surface Area | \(\pi r l\) | \(\pi (6)(10) = 60\pi\) cm\(^2\) |
| Total Surface Area | \(\pi r^2 + \pi r l\) | \(36\pi + 60\pi = 96\pi\) cm\(^2\) |
| Numerical Value (\(\pi \approx 22/7\)) | \(96 \times \pi\) | \(96 \times \frac{22}{7} \approx 301.71\) cm\(^2\) |
| Measurement | Formula | Variables |
|---|---|---|
| Radius | \(r\) | Given or calculated |
| Height | \(h\) | Given or calculated |
| Slant Height | \(l = \sqrt{r^2 + h^2}\) | \(r\) (radius), \(h\) (height) |
| Base Area | \(\pi r^2\) | \(r\) (radius) |
| Lateral Surface Area | \(\pi r l\) | \(r\) (radius), \(l\) (slant height) |
| Total Surface Area | \(\pi r (r + l)\) | \(r\) (radius), \(l\) (slant height) |
| Volume | \(\frac{1}{3}\pi r^2 h\) | \(r\) (radius), \(h\) (height) |
A cone is a three-dimensional geometric shape that tapers smoothly from a flat base (usually circular) to a point called the apex or vertex. Here are some important terms related to cones:
Understanding the relationship between the height, radius, and slant height via the Pythagorean theorem is crucial for solving many cone-related problems, especially those involving surface area and finding missing dimensions.
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