All Exams Test series for 1 year @ ₹349 only
Question

The volume of a cone is 73920 cm3. If the height of the cone is 160 cm, then find the diameter of its base.

This question was previously asked in
SSC CGL 2023 (Tier-II) Paper 1 Previous Year Paper (26-Oct-2023) (Shift-1)
The correct answer is

42 cm

Understanding the Cone Volume Problem

This problem asks us to find the diameter of the base of a cone, given its volume and its height. A cone is a three-dimensional geometric shape that tapers smoothly from a flat base (usually circular) to a point called the apex or vertex.

We are provided with the following information:

  • Volume of the cone (\(V\)) = 73920 cm3
  • Height of the cone (\(h\)) = 160 cm

Our goal is to determine the diameter (\(d\)) of the circular base.

Cone Volume Formula Explained

The volume of a cone is calculated using a standard formula that relates its height and the radius of its base. The formula is:

\(V = \frac{1}{3} \pi r^2 h\)

Where:

  • \(V\) is the volume of the cone
  • \(\pi\) (pi) is a mathematical constant, approximately equal to 3.14159 or \(\frac{22}{7}\)
  • \(r\) is the radius of the circular base
  • \(h\) is the height of the cone

The diameter (\(d\)) of the base is twice the radius (\(r\)), so \(d = 2r\).

Step-by-Step Calculation of Cone Radius

To find the diameter, we first need to find the radius (\(r\)) of the base using the given volume and height. We can rearrange the volume formula to solve for \(r^2\):

\(V = \frac{1}{3} \pi r^2 h\)

Multiply both sides by 3:

\(3V = \pi r^2 h\)

Divide both sides by \(\pi h\):

\(r^2 = \frac{3V}{\pi h}\)

Now, substitute the given values for \(V\) and \(h\) into this formula. We will use \(\pi = \frac{22}{7}\) for the calculation.

\(r^2 = \frac{3 \times 73920}{\frac{22}{7} \times 160}\)

To simplify the calculation, we can rewrite the denominator:

\(r^2 = \frac{3 \times 73920}{\frac{22 \times 160}{7}}\)

Multiply the numerator by the reciprocal of the denominator:

\(r^2 = \frac{3 \times 73920 \times 7}{22 \times 160}\)

Calculate the values:

\(3 \times 73920 = 221760\)

\(22 \times 160 = 3520\)

So, the equation becomes:

\(r^2 = \frac{221760 \times 7}{3520}\)

Now, perform the multiplication in the numerator:

\(r^2 = \frac{1552320}{3520}\)

Perform the division:

\(r^2 = 441\)

To find \(r\), take the square root of both sides:

\(r = \sqrt{441}\)

\(r = 21 \text{ cm}\)

The radius of the base is 21 cm.

Calculating the Cone Base Diameter

The diameter of the base is simply twice the radius.

\(d = 2r\)

Substitute the calculated radius value:

\(d = 2 \times 21 \text{ cm}\)

\(d = 42 \text{ cm}\)

Thus, the diameter of the base of the cone is 42 cm.

Revision Table: Cone Geometry Formulas

Measurement Formula Variables
Volume (\(V\)) \(\frac{1}{3} \pi r^2 h\) \(r\) = radius, \(h\) = height
Base Area \(\pi r^2\) \(r\) = radius
Circumference of Base \(2\pi r\) or \(\pi d\) \(r\) = radius, \(d\) = diameter
Diameter (\(d\)) \(2r\) \(r\) = radius

Additional Information on Cones

Cones are fascinating geometric shapes. Here are a few more key terms and concepts related to cones:

  • Slant Height (\(l\)): The distance from the apex to any point on the circumference of the base. In a right cone (where the apex is directly above the center of the base), the height, radius, and slant height are related by the Pythagorean theorem: \(l^2 = r^2 + h^2\).
  • Surface Area: A cone has two surfaces: the base and the lateral surface.
    • Area of the base = \(\pi r^2\)
    • Lateral surface area = \(\pi r l\)
    • Total surface area = Area of base + Lateral surface area = \(\pi r^2 + \pi r l = \pi r (r + l)\)
  • Types of Cones: The cone discussed here is a right circular cone. Oblique cones have the apex not directly above the center of the base.

Understanding these concepts helps in solving various problems involving cones, such as finding surface area or slant height.

Was this answer helpful?

Similar Questions

  1. If the total surface area of a cube is 24 sq.units, then what is the volume of the cube?

  2. Ranu carries water to school in a cylindrical flask with diameter 12 cm and height 21 cm. Determine the amount of water that she can carry in the flask. (Use π = \(\frac{22}{7}\))

  3. The volume of a cone with height equal to radius, and slant height 5 cm is :

  4. What is the whole surface area of a cone of base radius 6 cm and height 8 cm?

  5. What is the volume of a cube if the perimeter of one face of the cube is 40 cm?

  6. A spherical ball of lead, 3 cm in diameter, is melted and recast into three spherical balls. The diameters of two of these balls are \(\frac{3}{2}\) cm and 2 cm, respectively. Find the diameter of the third ball.  

  7. A conical tent of height 10 m and base diameter 48 m was erected by a company in a park. Find the curved surface area of the tent (In m2).

  8. If the surface area of a cube is 5046 cm2, then the volume of the cube is:

  9. The volume of a cuboid is twice that of a cube. If the dimensions of the cuboid are (8 m × 8 m ×16 m), the total surface area of the cube is: 

  10. If the slant height of a cone is 60 cm and the radius of its base is 21 cm, then find its curved surface area. (use π = \({22 \ {} \over 7}\))


Important Questions from Solid Figures

  1. The area of the floor of a cubical room is 192 m 2. The length of the longest rod that can be kept in that room is :

  2. A solid metallic rectangular block of dimensions 112 cm × 44 cm × 25 cm is melted and recast into a cylinder of radius 35 cm. The curved surface area (in cm 2) of the cylinder is: (Take π = 22/7)

  3. If the volume of a cube is 175616 cm 3, what is its side?

  4. The volume of a right circular cone is 1232 cm 3. If the height of the cone is 24 cm, then what will be the radius of its base?

  5. A right triangle contains the right angle between the sides 5 cm and 7 cm. A cone is generated by revolving about the side 5 cm. The volume of this cone is:

Need Expert Advice?
Upcoming Exams
SSC JHT
September 08, 2026
SSC Stenographer
September 09, 2026
SSC Selection Post
September 16, 2026
Test Series
SSC CGL img
SSC
SSC CGL (Tier I + Tier II) 2026 Mock Test Series - Latest Pattern
2500 Tests 6 Tests Free
3944 Attempts
4.2(838)
English, Hindi

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App