The volume of a cone is 73920 cm3. If the height of the cone is 160 cm, then find the diameter of its base.
42 cm
This problem asks us to find the diameter of the base of a cone, given its volume and its height. A cone is a three-dimensional geometric shape that tapers smoothly from a flat base (usually circular) to a point called the apex or vertex.
We are provided with the following information:
Our goal is to determine the diameter (\(d\)) of the circular base.
The volume of a cone is calculated using a standard formula that relates its height and the radius of its base. The formula is:
\(V = \frac{1}{3} \pi r^2 h\)
Where:
The diameter (\(d\)) of the base is twice the radius (\(r\)), so \(d = 2r\).
To find the diameter, we first need to find the radius (\(r\)) of the base using the given volume and height. We can rearrange the volume formula to solve for \(r^2\):
\(V = \frac{1}{3} \pi r^2 h\)
Multiply both sides by 3:
\(3V = \pi r^2 h\)
Divide both sides by \(\pi h\):
\(r^2 = \frac{3V}{\pi h}\)
Now, substitute the given values for \(V\) and \(h\) into this formula. We will use \(\pi = \frac{22}{7}\) for the calculation.
\(r^2 = \frac{3 \times 73920}{\frac{22}{7} \times 160}\)
To simplify the calculation, we can rewrite the denominator:
\(r^2 = \frac{3 \times 73920}{\frac{22 \times 160}{7}}\)
Multiply the numerator by the reciprocal of the denominator:
\(r^2 = \frac{3 \times 73920 \times 7}{22 \times 160}\)
Calculate the values:
\(3 \times 73920 = 221760\)
\(22 \times 160 = 3520\)
So, the equation becomes:
\(r^2 = \frac{221760 \times 7}{3520}\)
Now, perform the multiplication in the numerator:
\(r^2 = \frac{1552320}{3520}\)
Perform the division:
\(r^2 = 441\)
To find \(r\), take the square root of both sides:
\(r = \sqrt{441}\)
\(r = 21 \text{ cm}\)
The radius of the base is 21 cm.
The diameter of the base is simply twice the radius.
\(d = 2r\)
Substitute the calculated radius value:
\(d = 2 \times 21 \text{ cm}\)
\(d = 42 \text{ cm}\)
Thus, the diameter of the base of the cone is 42 cm.
| Measurement | Formula | Variables |
|---|---|---|
| Volume (\(V\)) | \(\frac{1}{3} \pi r^2 h\) | \(r\) = radius, \(h\) = height |
| Base Area | \(\pi r^2\) | \(r\) = radius |
| Circumference of Base | \(2\pi r\) or \(\pi d\) | \(r\) = radius, \(d\) = diameter |
| Diameter (\(d\)) | \(2r\) | \(r\) = radius |
Cones are fascinating geometric shapes. Here are a few more key terms and concepts related to cones:
Understanding these concepts helps in solving various problems involving cones, such as finding surface area or slant height.
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