What is the volume of a cube if the perimeter of one face of the cube is 40 cm?
1000 cm3
The question asks us to find the volume of a cube given the perimeter of one of its faces. A key piece of information here is that a face of a cube is always a square. The volume of a cube depends on the length of its side.
Here's how we can solve this problem:
$\text{Perimeter} = 4 \times \text{side}$
$40 \text{ cm} = 4 \times \text{side}$
To find the side, we divide the perimeter by 4:
$\text{side} = \frac{40 \text{ cm}}{4}$
$\text{side} = 10 \text{ cm}$
So, the length of one side of the square face is 10 cm.
$V = (10 \text{ cm})^3$
$V = 10 \text{ cm} \times 10 \text{ cm} \times 10 \text{ cm}$
$V = 1000 \text{ cm}^3$
Based on our calculation, the volume of the cube with a face perimeter of 40 cm is 1000 cm$^3$. This matches one of the provided options.
| Step | Description | Calculation |
|---|---|---|
| 1 | Perimeter of face (square) | 40 cm |
| 2 | Formula for square perimeter | $P = 4 \times \text{side}$ |
| 3 | Calculate side of square face | $\text{side} = \frac{P}{4} = \frac{40}{4} = 10 \text{ cm}$ |
| 4 | Side of cube | 10 cm |
| 5 | Formula for cube volume | $V = \text{side}^3$ |
| 6 | Calculate cube volume | $V = (10 \text{ cm})^3 = 1000 \text{ cm}^3$ |
| Property | Formula (s = side length) |
|---|---|
| Perimeter of a face (square) | $4s$ |
| Area of a face (square) | $s^2$ |
| Total Surface Area | $6s^2$ |
| Volume | $s^3$ |
| Diagonal of a face | $s\sqrt{2}$ |
| Space diagonal of cube | $s\sqrt{3}$ |
A cube is a special type of rectangular prism where all edges are equal in length. It is one of the five Platonic solids. Understanding the properties of a cube is essential for solving geometry problems related to volume, surface area, and dimensions.
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