If the total surface area of a cube is 24 sq.units, then what is the volume of the cube?
8 cu.units
The problem asks us to find the volume of a cube given its total surface area. We are provided with the total surface area as 24 square units.
To solve this, we need to use the formulas for the surface area and volume of a cube.
Step 1: Find the side length of the cube.
We know the total surface area is 24 sq. units. Using the surface area formula:
$\text{Total Surface Area} = 6s^2$
$24 = 6s^2$
To find $s^2$, we divide the total surface area by 6:
$s^2 = \frac{24}{6}$
$s^2 = 4$
Now, to find the side length 's', we take the square root of 4:
$s = \sqrt{4}$
Since the side length must be a positive value:
$s = 2$ units
So, the length of each side of the cube is 2 units.
Step 2: Calculate the volume of the cube.
Now that we have the side length, we can use the volume formula:
$\text{Volume} = s^3$
Substitute the value of 's' we found:
$\text{Volume} = (2)^3$
$\text{Volume} = 2 \times 2 \times 2$
$\text{Volume} = 8$ cubic units
Thus, the volume of the cube is 8 cubic units.
Let's verify with the options provided:
| Option | Volume | Matches Calculation? |
|---|---|---|
| 1 | 8 cu.units | Yes |
| 2 | 16 cu.units | No |
| 3 | 10 cu.units | No |
| 4 | 4 cu.units | No |
Our calculated volume matches the first option.
| Property | Formula (side = s) | Description |
|---|---|---|
| Side Length | s | Length of one edge of the cube |
| Total Surface Area | $6s^2$ | Sum of the areas of all 6 faces |
| Volume | $s^3$ | Space occupied by the cube |
A cube is a three-dimensional solid object bounded by six square faces, facets or sides, with three meetings at each vertex. It is a type of hexahedron.
Problems involving cubes often require you to use these fundamental formulas to find unknown dimensions or properties based on known values.
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