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Question

What is the value of the determinant of the inverse of the matrix $\begin{bmatrix} -4 & -5 \\ 2 & 2 \end{bmatrix}$?

The correct answer is
$\frac{1}{2}$

Solving for the Determinant of an Inverse Matrix

This problem asks us to find the value of the determinant of the inverse of a given 2x2 matrix. Let the matrix be denoted by A.

$A = \begin{bmatrix} -4 & -5 \\ 2 & 2 \end{bmatrix}$

We need to find $det(A^{-1})$.

Key Concepts for Matrix Determinants

There are a couple of important properties of determinants that make this calculation simpler:

  • The determinant of a 2x2 matrix $\begin{bmatrix} a & b \\ c & d \end{bmatrix}$ is calculated as $ad - bc$.
  • A crucial property relating a matrix and its inverse is: $det(A^{-1}) = \frac{1}{det(A)}$. This means we don't need to calculate the inverse matrix itself to find its determinant.

Step 1: Calculate the Determinant of the Original Matrix (A)

First, let's find the determinant of the given matrix A using the formula $ad - bc$.

For matrix $A = \begin{bmatrix} -4 & -5 \\ 2 & 2 \end{bmatrix}$, we have $a = -4$, $b = -5$, $c = 2$, and $d = 2$.

Calculating the determinant:

$det(A) = (-4)(2) - (-5)(2)$
$det(A) = -8 - (-10)$
$det(A) = -8 + 10$
$det(A) = 2$

Step 2: Use the Determinant Property to Find $det(A^{-1})$

Now, we apply the property $det(A^{-1}) = \frac{1}{det(A)}$.

Since we found that $det(A) = 2$, we can substitute this value:

$det(A^{-1}) = \frac{1}{2}$

Conclusion

The value of the determinant of the inverse of the matrix $\begin{bmatrix} -4 & -5 \\ 2 & 2 \end{bmatrix}$ is $\frac{1}{2}$.

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Important Questions from Matrices and Determinants

  1. In obtaining the solution of the system of equations $x + y + z = 7$, $x + 2y+3z = 16$ and $x + 3y+4z = 22$ by Cramer's rule, the value of $y$ is obtained by dividing $D$ by $D_2$, where 

    $D = \begin{vmatrix} 1 & 1 & 1 \\ 1 & 2 & 3 \\ 1 & 3 & 4 \end{vmatrix}$ 

    What is the value of the determinant $D_2$?

  2. Consider the following in respect of non-singular matrices $A$ and $B$ : 

    I. $(AB)^{-1} = A^{-1}B^{-1}$ 

    II. $(BA)(AB)^{-1} = I$, where $I$ is the identity matrix 

    III. $(AB)^T = A^T B^T$ 

    How many of the above are correct?

  3. Consider the following statements : 

    Statement-I : 

    If $X$ is an $n \times n$ matrix, then $\det(mX) = m^n \det(X)$, where $m$ is a scalar. 

    Statement-II : 

    If $Y$ is a matrix obtained from $X$ by multiplying any row or column by a scalar $m$, then $\det(Y) = m\det(X)$. 

    Which one of the following is correct in respect of the above statements?

  4. Consider the following statements about the matrix $M = \begin{vmatrix} 71 & 23 & 48 \\ 57 & 28 & 29 \\ 65 & 17 & 48 \end{vmatrix}$ 

    Statement-I : The inverse of $M$ does not exist. 

    Statement-II : $M$ is non-singular. 

    Which one of the following is correct in respect of the above statements?

  5. Let $f(x) = \begin{vmatrix} 3x^2 & \cos x & -\sin x \\ 6 & -1 & 0 \\ q & q^2 & q^3 \end{vmatrix}$ where q is any constant, then what is $\frac{d^2}{dx^2}(f(x))$ at $x = 0$ equal to ?
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