Let \(A\) and \(B\) be matrices of order \(3 \times 3\)., If \(|A| = \frac{1}{2\sqrt{2}}\) and \(|B| = \frac{1}{729}\), then what is the value of \(|2B(\text{adj}(3A))|\)?
This problem asks us to find the value of the determinant \(|2B(\text{adj}(3A))|\) given the determinants of two \(3 \times 3\) matrices, \(A\) and \(B\). We are given that \(|A| = \frac{1}{2\sqrt{2}}\) and \(|B| = \frac{1}{729}\). The order of the matrices is \(n=3\).
To solve this, we need to use several key properties of determinants:
Let's break down the calculation of \(|2B(\text{adj}(3A))|\) step by step:
Using the property \(|XY| = |X||Y|\), we can write:
\(|2B(\text{adj}(3A))| = |2B| \times |\text{adj}(3A)|\)Here, \(k=2\) and the order \(n=3\). Using the scalar multiple property \(|kA| = k^n |A|\):
\(|2B| = 2^3 |B|\) \(|2B| = 8 \times |B|\)Substituting the given value \(|B| = \frac{1}{729}\):
\(|2B| = 8 \times \frac{1}{729} = \frac{8}{729}\)This requires two sub-steps:
Now substitute the expression for \(|3A|\) from the previous step:
\(|\text{adj}(3A)| = (27 |A|)^2\) \(|\text{adj}(3A)| = 27^2 \times |A|^2\) \(|\text{adj}(3A)| = 729 \times |A|^2\)Substitute the given value \(|A| = \frac{1}{2\sqrt{2}}\):
\(|A|^2 = \left(\frac{1}{2\sqrt{2}}\right)^2 = \frac{1}{(2\sqrt{2})^2} = \frac{1}{4 \times 2} = \frac{1}{8}\)So, the determinant of the adjugate is:
\(|\text{adj}(3A)| = 729 \times \frac{1}{8} = \frac{729}{8}\)Now substitute the values calculated in Step 2 and Step 3 back into the equation from Step 1:
\(|2B(\text{adj}(3A))| = |2B| \times |\text{adj}(3A)|\) \(|2B(\text{adj}(3A))| = \frac{8}{729} \times \frac{729}{8}\)The terms cancel out:
\(|2B(\text{adj}(3A))| = 1\)Therefore, the value of \(|2B(\text{adj}(3A))|\) is 1.
If $A = \begin{bmatrix} \sin 2\theta & 2 \sin^2 \theta - 1 & 0 \\ \cos 2\theta & 2 \sin \theta \cos \theta & 0 \\ 0 & 0 & 1 \end{bmatrix}$, then which of the following statements is/are correct?
1. $A^{-1} = \text{adj}A$
2. $A$ is skew-symmetric matrix
3. $A^{-1} = A^T$
Select the correct answer using the code given below :
If
\(\omega = -\frac{1}{2} + i\frac{\sqrt{3}}{2}\)
then what is
equal to?