Problem Analysis: The question asks for the value of \(k\) given an equation involving two determinants. The determinant on the left involves differences between elements, while the one on the right is a standard determinant.
Let the given equation be:
\( D_1 = \begin{vmatrix} a-b & p-q & x-y \\ b-c & q-r & y-z \\ c-a & r-p & z-x \end{vmatrix} = k \begin{vmatrix} a & b & c \\ p & q & r \\ x & y & z \end{vmatrix} = k \cdot D_2 \)
We can use row operations to simplify \(D_1\). Apply the operation \(R1 → R1 + R2 + R3\).
After this operation, the determinant \(D_1\) becomes:
\( D_1 = \begin{vmatrix} 0 & 0 & 0 \\ b-c & q-r & y-z \\ c-a & r-p & z-x \end{vmatrix} \)
A fundamental property of determinants is that if a matrix has a row (or column) consisting entirely of zeros, its determinant is zero.
Therefore, \(D_1 = 0\).
Substitute the value of \(D_1\) back into the original equation:
\(0 = k \cdot D_2\)
Where \(D_2 = \begin{vmatrix} a & b & c \\ p & q & r \\ x & y & z \end{vmatrix}\).
For this equation to hold true generally (assuming \(D_2\) is not necessarily zero), the value of \(k\) must be 0.
The value of \(k\) is 0.
Let \(A\) and \(B\) be matrices of order \(3 \times 3\)., If \(|A| = \frac{1}{2\sqrt{2}}\) and \(|B| = \frac{1}{729}\), then what is the value of \(|2B(\text{adj}(3A))|\)?
If $A = \begin{bmatrix} \sin 2\theta & 2 \sin^2 \theta - 1 & 0 \\ \cos 2\theta & 2 \sin \theta \cos \theta & 0 \\ 0 & 0 & 1 \end{bmatrix}$, then which of the following statements is/are correct?
1. $A^{-1} = \text{adj}A$
2. $A$ is skew-symmetric matrix
3. $A^{-1} = A^T$
Select the correct answer using the code given below :
If
\(\omega = -\frac{1}{2} + i\frac{\sqrt{3}}{2}\)
then what is
equal to?
Let \(A\) and \(B\) be matrices of order \(3 \times 3\)., If \(|A| = \frac{1}{2\sqrt{2}}\) and \(|B| = \frac{1}{729}\), then what is the value of \(|2B(\text{adj}(3A))|\)?