Consider the following for the two (02) items that follow: Let
\(\begin{vmatrix}1 & 0 & 0 \\0 & 1 & 0 \\0 & 0 & 1\end{vmatrix}\)
The question asks us to find the value of the expression \(A(\text{adj } A)\) for a given \(3 \times 3\) matrix \(A\).
We are given the matrix:
| \[A = \begin{vmatrix}3 & -3 & 4 \\2 & -3 & 4 \\0 & -1 & 1\end{vmatrix}\] |
A fundamental property relating a matrix \(A\), its adjugate matrix (\(\text{adj } A\)), and its determinant (\(|A|\)) is:
\[A(\text{adj } A) = (\text{adj } A)A = |A|I\]
where \(I\) is the identity matrix of the same order as \(A\).
To find \(A(\text{adj } A)\), we first need to calculate the determinant of matrix \(A\), denoted as \(|A|\).
The determinant of a \(3 \times 3\) matrix \(\begin{vmatrix}a & b & c \\d & e & f \\g & h & i\end{vmatrix}\) is calculated as \(a(ei - fh) - b(di - fg) + c(dh - eg)\).
For our matrix \(A = \begin{vmatrix}3 & -3 & 4 \\2 & -3 & 4 \\0 & -1 & 1\end{vmatrix}\), the determinant is:
\[|A| = 3 \begin{vmatrix}-3 & 4 \\-1 & 1\end{vmatrix} - (-3) \begin{vmatrix}2 & 4 \\0 & 1\end{vmatrix} + 4 \begin{vmatrix}2 & -3 \\0 & -1\end{vmatrix}\]
Let's compute the determinants of the \(2 \times 2\) matrices:
Now substitute these values back into the determinant formula for \(A\):
\[|A| = 3(1) - (-3)(2) + 4(-2)\]
\[|A| = 3 + 6 - 8\]
\[|A| = 9 - 8\]
\[|A| = 1\]
We found that the determinant of matrix \(A\) is \(|A| = 1\). Using the property \(A(\text{adj } A) = |A|I\), we can substitute the value of \(|A|\):
\[A(\text{adj } A) = (1)I\]
Since \(A\) is a \(3 \times 3\) matrix, the identity matrix \(I\) must also be a \(3 \times 3\) identity matrix:
\[I = \begin{vmatrix}1 & 0 & 0 \\0 & 1 & 0 \\0 & 0 & 1\end{vmatrix}\]
Therefore, multiplying the identity matrix by 1 gives:
\[A(\text{adj } A) = 1 \cdot \begin{vmatrix}1 & 0 & 0 \\0 & 1 & 0 \\0 & 0 & 1\end{vmatrix} = \begin{vmatrix}1 & 0 & 0 \\0 & 1 & 0 \\0 & 0 & 1\end{vmatrix}\]
The expression \(A(\text{adj } A)\) is equal to the \(3 \times 3\) identity matrix.
| \[\begin{vmatrix}1 & 0 & 0 \\0 & 1 & 0 \\0 & 0 & 1\end{vmatrix}\] |
Let \(A\) and \(B\) be matrices of order \(3 \times 3\)., If \(|A| = \frac{1}{2\sqrt{2}}\) and \(|B| = \frac{1}{729}\), then what is the value of \(|2B(\text{adj}(3A))|\)?
If $A = \begin{bmatrix} \sin 2\theta & 2 \sin^2 \theta - 1 & 0 \\ \cos 2\theta & 2 \sin \theta \cos \theta & 0 \\ 0 & 0 & 1 \end{bmatrix}$, then which of the following statements is/are correct?
1. $A^{-1} = \text{adj}A$
2. $A$ is skew-symmetric matrix
3. $A^{-1} = A^T$
Select the correct answer using the code given below :
If
\(\omega = -\frac{1}{2} + i\frac{\sqrt{3}}{2}\)
then what is
equal to?
Let \(A\) and \(B\) be matrices of order \(3 \times 3\)., If \(|A| = \frac{1}{2\sqrt{2}}\) and \(|B| = \frac{1}{729}\), then what is the value of \(|2B(\text{adj}(3A))|\)?