What is the perimeter of a square inscribed in a circle of radius 5 cm?
20√2 cm
Let's find the perimeter of a square inscribed in a circle. We are given that the radius of the circle is 5 cm.
When a square is inscribed in a circle, it means that all four vertices (corners) of the square lie on the circumference of the circle. In this arrangement, the diagonal of the square is also the diameter of the circle.
Since the diagonal of the inscribed square is equal to the diameter of the circle, the diagonal of the square is 10 cm.
Let the side length of the square be 's'. In a square, the relationship between the side length (s) and the diagonal (d) is given by the Pythagorean theorem. If we consider one of the right-angled triangles formed by the diagonal and two sides of the square, we have:
\(s^2 + s^2 = d^2\)
\(2s^2 = d^2\)
We know the diagonal \(d = 10\) cm. Let's substitute this value:
\(2s^2 = 10^2\)
\(2s^2 = 100\)
Now, we solve for \(s^2\):
\(s^2 = \frac{100}{2}\)
\(s^2 = 50\)
To find the side length 's', we take the square root of 50:
\(s = \sqrt{50}\)
We can simplify \(\sqrt{50}\) by factoring 50 as \(25 \times 2\):
\(s = \sqrt{25 \times 2}\)
\(s = \sqrt{25} \times \sqrt{2}\)
\(s = 5\sqrt{2}\) cm
So, the side length of the square is \(5\sqrt{2}\) cm.
The perimeter of a square is the sum of the lengths of its four sides. Since all sides of a square are equal, the perimeter is 4 times the side length.
Perimeter \(P = 4 \times s\)
Substitute the side length \(s = 5\sqrt{2}\) cm:
\(P = 4 \times (5\sqrt{2})\)
\(P = (4 \times 5) \times \sqrt{2}\)
\(P = 20\sqrt{2}\) cm
The perimeter of the square inscribed in the circle with a radius of 5 cm is \(20\sqrt{2}\) cm.
Here is a summary of the values:
| Measurement | Value |
|---|---|
| Circle Radius | 5 cm |
| Circle Diameter (Square Diagonal) | 10 cm |
| Square Side Length | \(5\sqrt{2}\) cm |
| Square Perimeter | \(20\sqrt{2}\) cm |
| Concept | Formula / Relationship | Notes |
|---|---|---|
| Circle Diameter (d) | \(d = 2r\) | 'r' is the circle radius |
| Square Diagonal (ds) in Inscribed Square | \(d_s = d_{circle}\) | Diagonal equals circle diameter |
| Square Side (s) from Diagonal (ds) | \(s = \frac{d_s}{\sqrt{2}}\) or \(d_s = s\sqrt{2}\) | From Pythagorean theorem: \(s^2+s^2 = d_s^2\) |
| Square Perimeter (P) | \(P = 4s\) | Sum of the four equal sides |
Understanding inscribed shapes helps in solving many geometry problems. Here are a few related concepts:
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