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Question

What is the perimeter of a square inscribed in a circle of radius 5 cm?

This question was previously asked in
SSC CGL 2022 Tier-II (Paper 2 JSO) Previous Year Paper (04-Mar-2023)
The correct answer is

20√2 cm

Let's find the perimeter of a square inscribed in a circle. We are given that the radius of the circle is 5 cm.

Understanding Inscribed Shapes

When a square is inscribed in a circle, it means that all four vertices (corners) of the square lie on the circumference of the circle. In this arrangement, the diagonal of the square is also the diameter of the circle.

  • Radius of the circle (r): 5 cm
  • Diameter of the circle (d): The diameter is twice the radius. So, \(d = 2 \times r = 2 \times 5\) cm.
  • \(d = 10\) cm

Since the diagonal of the inscribed square is equal to the diameter of the circle, the diagonal of the square is 10 cm.

Finding the Side Length of the Square

Let the side length of the square be 's'. In a square, the relationship between the side length (s) and the diagonal (d) is given by the Pythagorean theorem. If we consider one of the right-angled triangles formed by the diagonal and two sides of the square, we have:

\(s^2 + s^2 = d^2\)

\(2s^2 = d^2\)

We know the diagonal \(d = 10\) cm. Let's substitute this value:

\(2s^2 = 10^2\)

\(2s^2 = 100\)

Now, we solve for \(s^2\):

\(s^2 = \frac{100}{2}\)

\(s^2 = 50\)

To find the side length 's', we take the square root of 50:

\(s = \sqrt{50}\)

We can simplify \(\sqrt{50}\) by factoring 50 as \(25 \times 2\):

\(s = \sqrt{25 \times 2}\)

\(s = \sqrt{25} \times \sqrt{2}\)

\(s = 5\sqrt{2}\) cm

So, the side length of the square is \(5\sqrt{2}\) cm.

Calculating the Perimeter of the Square

The perimeter of a square is the sum of the lengths of its four sides. Since all sides of a square are equal, the perimeter is 4 times the side length.

Perimeter \(P = 4 \times s\)

Substitute the side length \(s = 5\sqrt{2}\) cm:

\(P = 4 \times (5\sqrt{2})\)

\(P = (4 \times 5) \times \sqrt{2}\)

\(P = 20\sqrt{2}\) cm

The perimeter of the square inscribed in the circle with a radius of 5 cm is \(20\sqrt{2}\) cm.

Summary of Steps

  • Identify the relationship between the circle's diameter and the square's diagonal when the square is inscribed in the circle.
  • Calculate the circle's diameter (which equals the square's diagonal) using the given radius.
  • Use the diagonal to find the side length of the square using the Pythagorean theorem or the formula \(s = d/\sqrt{2}\).
  • Calculate the perimeter of the square using the formula \(P = 4s\).

Here is a summary of the values:

Measurement Value
Circle Radius 5 cm
Circle Diameter (Square Diagonal) 10 cm
Square Side Length \(5\sqrt{2}\) cm
Square Perimeter \(20\sqrt{2}\) cm

Revision Table: Inscribed Square Geometry

Concept Formula / Relationship Notes
Circle Diameter (d) \(d = 2r\) 'r' is the circle radius
Square Diagonal (ds) in Inscribed Square \(d_s = d_{circle}\) Diagonal equals circle diameter
Square Side (s) from Diagonal (ds) \(s = \frac{d_s}{\sqrt{2}}\) or \(d_s = s\sqrt{2}\) From Pythagorean theorem: \(s^2+s^2 = d_s^2\)
Square Perimeter (P) \(P = 4s\) Sum of the four equal sides

Additional Information: Related Geometric Concepts

Understanding inscribed shapes helps in solving many geometry problems. Here are a few related concepts:

  • Circumscribed Square: A square is circumscribed around a circle if all four sides of the square are tangent to the circle. In this case, the side length of the square is equal to the diameter of the circle.
  • Area of Inscribed Square: If the side length is \(s\), the area is \(s^2\). Using the diagonal \(d = 2r\), \(s = d/\sqrt{2} = 2r/\sqrt{2} = r\sqrt{2}\). Area \(= (r\sqrt{2})^2 = 2r^2\).
  • Area of Circumscribed Square: If the side length is \(s = d = 2r\), the area is \(s^2 = (2r)^2 = 4r^2\). Notice the area of a circumscribed square is twice the area of an inscribed square for the same circle.
  • Inscribed Circle in a Square: If a circle is inscribed in a square, the diameter of the circle is equal to the side length of the square.
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Similar Questions

  1. The bisector of ∠B in ΔABC meets AC at D. If AB = 12 cm, BC = 18 cm and AC = 15 cm, then the length of AD (in cm) is:

  2. The perimeter of a semi circle is 25.7 cm. What is its diameter (in cm)? (π = 3.14)

  3. A square has the perimeter equal to the circumference of a circle having radius 7 cm. What is the ratio of the area of the circle to area of the square? (Use π = 22/7)

  4. ABC is an equilateral triangle with side 12 cm. What is the length of the radius of the circle inscribed in it ?

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  6. D and E are points on side AB and AC of ΔABC. DE is parallel to BC. If AD : DB = 2 : 3 and area of ΔABC is 100 sq cm, what is the area (in sq cm) of quadrilateral BDEC?

  7. InABC , ∠A = 88°. If I is the incentre of the triangle, then the measure of ∠BICis:

  8. Chords AB and CD of a circle intersect externally at P. If AB = 7 cm, CD = 1 cm and PD = 5 cm, then the length of PB (in cm) is:

  9. If length of a rectangle is increased to its three times and breadth is decreased to its half, then the ratio of the area of given rectangle to the area of new rectangle is:

  10. The length of the chord of a circle is 24 cm, and the perpendicular distance between the centre and the chord is 5 cm. The radius of the circle is:


Important Questions from Plane Figures

  1. If the area of a square is 625 cm 2, then what is the perimeter of the square?

  2. The area and the perimeter of a sheet of paper are 240 cm 2and 68 cm, respectively. What would be its length and breadth?

  3. One side of rectangular field is 15 meters and one of its diagonals is 17 meters. Then find the area of the field.

  4. The bisector of ∠B in ΔABC meets AC at D. If AB = 12 cm, BC = 18 cm and AC = 15 cm, then the length of AD (in cm) is:

  5. The perimeter and the length of one of the diagonals of a rhombus is 26 cm and 5 cm respectively. Find the length of its other diagonal (in cm).

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