All Exams Test series for 1 year @ ₹349 only
Question

What is the output of the following program ?

(Assume that the appropriate preprocessor directives are included and there is no syntax error)

main ( )

    {    char S[ ]="ABCDEFGH";

            printf ("%C", * (& S[3]));

            printf ("%s", S+4);

            printf ("%u", S);

    /* Base address of S is 1000 */

    }

This question was previously asked in
UGC NET 2015 Paper 1 Question Paper (27-Dec-2015)
The correct answer is

DEFGH1000

The expression *(&S[3]) is simply S[3], the fourth character 'D', which the character conversion prints.

S+4 points to 'E', so the %s conversion prints EFGH up to the terminating null.

The %u conversion prints the base address of S, given as 1000.

Output \(= \) D + EFGH + 1000 = DEFGH1000

Check: the three printf calls print 1, 4 and 4 characters, giving 9 characters in total.

Hence, DEFGH1000.

Was this answer helpful?

Similar Questions

  1. Which of the following statements about pointers in C are TRUE.

    (A) Pointers can be used to access array elements

    (B) Pointers can store the address of another pointer

    (C) Pointers are automatically deferenced in expression

    (D) Pointers cannot be used to access structure members

    Choose the correct answer from the options given below :

  2. What will be the output of the following C code?

    #include<stdio.h>

    void main()

    {

        int arr[5] = {10, 20, 30, 40, 50};

        int *p = (int*) (&arr + 1);

        printf("%d%d", *(arr + 1), *(p - 1));

    }

  3. Which of the following is correct way to declare a functional pointer in C ?

  4. Consider following C program :

    #include<stdio.h>

    int main()

    {

        int x[]={2, 4, 6, 8, 10};

        int a, b=0, *y=x+4;

        for(a=0; a<5; a++)

        {

            b=b+(*y-a)-*(y-a);

        }

            printf("%d\n", b);

            return 0;

    }

    What will be the output of the above C program ?

  5. Consider the following code :

    #include<stdio.h>

    void f1(char *x, char *y) {

        char *t1; t1=x; x=y; y=t1;}

    void f2(char **x, char **y) {

        char *t1; t1=*x; *x=*y; *y=t1;}

    int main()

    {

        char *a="ONE", *b="TWO";

        f1(a, b); printf("%s %s", a, b);

        f2(&a, &b); printf("%s %s", a, b);

        return 0;

    }

    What will be the output of the above code?

  6. #include<stdio.h>

    void main()

    {

        int arr[]={1, 2, 3, 4, 5};

        int *p=arr;

        printf("%d", *p++);

        printf("%d", *(p+1));

    }

    Find the output of the above code?

  7. What does the following expression means ?

    char *(*(* a[N]) ( )) ( );


Important Questions from Pointer

  1. What is the output of the following C programming language code? 

    #include<stdio.h>

     int main()

    { 

    int x = 10;

     int *p = &x;

     *p = *p + 5;

     printf("%d %d", x, *p); 

    return 0; 

    }

  2. The following statement in ‘C’
    int (*f())[ ];
    declares
  3. What would be the equivalent pointer expression for referring the array element ar[m][n][o]
  4. Only legal pointer operations:
    A. pointer + number $\rightarrow$ pointer
    B. pointer - number $\rightarrow$ number
    C. pointer + pointer $\rightarrow$ pointer
    D. pointer - pointer $\rightarrow$ pointer
    E. pointer - pointer $\rightarrow$ number
    Choose the most appropriate answer from the options given below:
  5. Consider the following ANSI-C program.

    #include <stdio.h>
    int main(){
     int *ptr, a, b, c;
     a=5; b=11; c=20;
     ptr=&a; *ptr=c; ptr=&c;
     a=*(&b); c=*ptr-a;
     printf("%d",c);
     return(0);
    }

    The output of this program is ____________. (answer in integer)

    Note: Assume that the program compiles and runs successfully.

Need Expert Advice?
Upcoming Exams
CTET
December 12, 2026
Test Series
UGC NET img
Teaching
UGC NET (Paper 2) 2026 Mock Test Series
796 Tests 2 Tests Free
4.4(39)
English
More Questions from UGC NET

Start Your Preparation with Prepp Mobile App

Download the app from Google Play & App Store
Download the app from Google Play & App Store
Prepp Mobile App