What is the output of the following program ? (Assume that the appropriate preprocessor directives are included and there is no syntax error) main ( ) { char S[ ]="ABCDEFGH"; printf ("%C", * (& S[3])); printf ("%s", S+4); printf ("%u", S); /* Base address of S is 1000 */ }
DEFGH1000
The expression *(&S[3]) is simply S[3], the fourth character 'D', which the character conversion prints.
S+4 points to 'E', so the %s conversion prints EFGH up to the terminating null.
The %u conversion prints the base address of S, given as 1000.
Output \(= \) D + EFGH + 1000 = DEFGH1000
Check: the three printf calls print 1, 4 and 4 characters, giving 9 characters in total.
Hence, DEFGH1000.
Which of the following statements about pointers in C are TRUE.
(A) Pointers can be used to access array elements
(B) Pointers can store the address of another pointer
(C) Pointers are automatically deferenced in expression
(D) Pointers cannot be used to access structure members
Choose the correct answer from the options given below :
What will be the output of the following C code?
#include<stdio.h>
void main()
{
int arr[5] = {10, 20, 30, 40, 50};
int *p = (int*) (&arr + 1);
printf("%d%d", *(arr + 1), *(p - 1));
}
Which of the following is correct way to declare a functional pointer in C ?
Consider following C program :
#include<stdio.h>
int main()
{
int x[]={2, 4, 6, 8, 10};
int a, b=0, *y=x+4;
for(a=0; a<5; a++)
{
b=b+(*y-a)-*(y-a);
}
printf("%d\n", b);
return 0;
}
What will be the output of the above C program ?
Consider the following code :
#include<stdio.h>
void f1(char *x, char *y) {
char *t1; t1=x; x=y; y=t1;}
void f2(char **x, char **y) {
char *t1; t1=*x; *x=*y; *y=t1;}
int main()
{
char *a="ONE", *b="TWO";
f1(a, b); printf("%s %s", a, b);
f2(&a, &b); printf("%s %s", a, b);
return 0;
}
What will be the output of the above code?
#include<stdio.h>
void main()
{
int arr[]={1, 2, 3, 4, 5};
int *p=arr;
printf("%d", *p++);
printf("%d", *(p+1));
}
Find the output of the above code?
What does the following expression means ?
char *(*(* a[N]) ( )) ( );
What is the output of the following C programming language code?
#include<stdio.h>
int main()
{
int x = 10;
int *p = &x;
*p = *p + 5;
printf("%d %d", x, *p);
return 0;
}
Consider the following ANSI-C program.
#include <stdio.h>
int main(){
int *ptr, a, b, c;
a=5; b=11; c=20;
ptr=&a; *ptr=c; ptr=&c;
a=*(&b); c=*ptr-a;
printf("%d",c);
return(0);
}
The output of this program is ____________. (answer in integer)
Note: Assume that the program compiles and runs successfully.