int (*f())[ ];
declares
To understand the declaration $int (*f())[ ];$, we break it down based on C's declaration rules (right-left parsing):
Therefore, the statement declares a function returning a pointer to an array of integers.
Consider the following C program:
#include <stdio.h>
void stringcopy(char *, char *);
int main(){
char a[30] = "@#Hello World!";
stringcopy(a, a + 2);
printf("%s\n", a);
return 0;
}
void stringcopy(char *s, char *t) {
while(*t)
*s++ = *t++;
}
Which ONE of the following will be the output of the program?
Consider the following C program:
#include <stdio.h>
int main(){
int a;
int arr[5] = {30,50,10};
int *ptr;
ptr = & arr[0] + 1;
a = *ptr;
(*ptr)++;
ptr++;
printf("%d", a + (*ptr) + arr[1]);
return 0;
}
The output of the above program is ____________ (Answer in integer)
Consider the following ANSI-C program.
#include <stdio.h>
int main(){
int *ptr, a, b, c;
a=5; b=11; c=20;
ptr=&a; *ptr=c; ptr=&c;
a=*(&b); c=*ptr-a;
printf("%d",c);
return(0);
}
The output of this program is ____________. (answer in integer)
Note: Assume that the program compiles and runs successfully.