#include<stdio.h> void main() { int arr[]={1, 2, 3, 4, 5}; int *p=arr; printf("%d", *p++); printf("%d", *(p+1)); } Find the output of the above code?
1, 3
In C, the expression *p++ is parsed as *(p++): the post-increment applies to the pointer, the old value of p is dereferenced, and p then moves to the next element.
Step 1 — p = arr points to arr[0] = 1.
Step 2 — printf("%d", *p++) prints the value at the old address, 1, and afterwards p points to arr[1] = 2.
Step 3 — *(p+1) is the element one place after arr[1], i.e. arr[2] = 3, so 3 is printed.
The program therefore prints 1 followed by 3 (written as 13 with no separator because the format strings contain none).
The pair 1, 2 would require *(p+1) to read arr[1]; 2, 3 would require the increment to happen before the first dereference; 1, 4 would require p to advance by two places.
1, 3 option is correct.
Similar Questions
What is the output of the following program ?
(Assume that the appropriate preprocessor directives are included and there is no syntax error)
main ( )
{ char S[ ]="ABCDEFGH";
printf ("%C", * (& S[3]));
printf ("%s", S+4);
printf ("%u", S);
/* Base address of S is 1000 */
}
Which of the following statements about pointers in C are TRUE.
(A) Pointers can be used to access array elements
(B) Pointers can store the address of another pointer
(C) Pointers are automatically deferenced in expression
(D) Pointers cannot be used to access structure members
Choose the correct answer from the options given below :
What will be the output of the following C code?
#include<stdio.h>
void main()
{
int arr[5] = {10, 20, 30, 40, 50};
int *p = (int*) (&arr + 1);
printf("%d%d", *(arr + 1), *(p - 1));
}
Which of the following is correct way to declare a functional pointer in C ?
Consider following C program :
#include<stdio.h>
int main()
{
int x[]={2, 4, 6, 8, 10};
int a, b=0, *y=x+4;
for(a=0; a<5; a++)
{
b=b+(*y-a)-*(y-a);
}
printf("%d\n", b);
return 0;
}
What will be the output of the above C program ?
Consider the following code :
#include<stdio.h>
void f1(char *x, char *y) {
char *t1; t1=x; x=y; y=t1;}
void f2(char **x, char **y) {
char *t1; t1=*x; *x=*y; *y=t1;}
int main()
{
char *a="ONE", *b="TWO";
f1(a, b); printf("%s %s", a, b);
f2(&a, &b); printf("%s %s", a, b);
return 0;
}
What will be the output of the above code?
What does the following expression means ?
char *(*(* a[N]) ( )) ( );
Important Questions from Pointer
What is the output of the following C programming language code?
#include<stdio.h>
int main()
{
int x = 10;
int *p = &x;
*p = *p + 5;
printf("%d %d", x, *p);
return 0;
}
- The following statement in ‘C’
int (*f())[ ];
declares - What would be the equivalent pointer expression for referring the array element ar[m][n][o]
- Only legal pointer operations:
A. pointer + number $\rightarrow$ pointer
B. pointer - number $\rightarrow$ number
C. pointer + pointer $\rightarrow$ pointer
D. pointer - pointer $\rightarrow$ pointer
E. pointer - pointer $\rightarrow$ number
Choose the most appropriate answer from the options given below: Consider the following ANSI-C program.
#include <stdio.h>
int main(){
int *ptr, a, b, c;
a=5; b=11; c=20;
ptr=&a; *ptr=c; ptr=&c;
a=*(&b); c=*ptr-a;
printf("%d",c);
return(0);
}
The output of this program is ____________. (answer in integer)
Note: Assume that the program compiles and runs successfully.
