The sum of the exterior angles of any convex polygon is always $360^{\circ}$.
For a regular polygon, all exterior angles are equal. If a regular polygon has $n$ sides, the measure of each exterior angle is calculated by dividing the total sum of exterior angles ($360^{\circ}$) by the number of sides ($n$).
Exterior Angle = $\frac{360^{\circ}}{n}$
Exterior Angle = $\frac{360^{\circ}}{15}$
Exterior Angle = $24^{\circ}$
Therefore, the exterior angle of a regular 15-sided polygon is $24^{\circ}$.
ABCDEF is a regular hexagon. Side of the hexagon is 36 cm. What is the area of the triangle AOB ?
If ∆ABC ~ ∆DEF, and BC = 4 cm, EF = 5 cm and the area of triangle ABC = 80 cm 2, then the area of the triangle DEF is:
If Δ ABC is right angled at B, AB = 12 cm and ∠CAB = 60°, determine the length of BC.
If ΔABC and ΔDEF are congruent triangles, then which of the following is FALSE?
D and E are points on the sides AB and AC, respectively, of ΔABC such that DE is parallel to BC and AD ∶ DB = 7 ∶ 9. If CD and BE intersect each other at F. then find the ratio of areas of ΔDEF and ΔCBF.