This problem requires finding the area and altitude of an equilateral triangle with a given side length.
The formula for the area of an equilateral triangle with side length '$a$' is:
$ \text{Area} = \frac{\sqrt{3}}{4} a^2 $
Given the side length '$a = 2$ cm':
$ \text{Area} = \frac{\sqrt{3}}{4} (2 \text{ cm})^2 $
$ \text{Area} = \frac{\sqrt{3}}{4} \times 4 \text{ cm}^2 $
$ \text{Area} = \sqrt{3} \text{ cm}^2 $
The formula for the altitude (height) '$h$' of an equilateral triangle with side length '$a$' is:
$ h = \frac{\sqrt{3}}{2} a $
Given the side length '$a = 2$ cm':
$ h = \frac{\sqrt{3}}{2} (2 \text{ cm}) $
$ h = \sqrt{3} \text{ cm} $
The calculated area is $\sqrt{3} \text{ cm}^2$ and the altitude is $\sqrt{3} \text{ cm}$.
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