To find the measure of each exterior angle of a regular octagon, we use the properties of polygons.
Identify the type of polygon. The question refers to a regular octagon.
Determine the number of sides ($n$) for the polygon. An octagon has $n = 8$ sides.
Use the formula for calculating each exterior angle of a regular polygon:
Exterior Angle = $\frac{\text{Sum of Exterior Angles}}{n}$
Exterior Angle = $\frac{360^\circ}{n}$
Substitute the value of $n$ for an octagon into the formula:
Exterior Angle = $\frac{360^\circ}{8}$
Calculate the result:
Exterior Angle = $45^\circ$
Therefore, the measure of each exterior angle of a regular octagon is $45^\circ$. This matches Option A.
ABCDEF is a regular hexagon. Side of the hexagon is 36 cm. What is the area of the triangle AOB ?
If ∆ABC ~ ∆DEF, and BC = 4 cm, EF = 5 cm and the area of triangle ABC = 80 cm 2, then the area of the triangle DEF is:
If Δ ABC is right angled at B, AB = 12 cm and ∠CAB = 60°, determine the length of BC.
If ΔABC and ΔDEF are congruent triangles, then which of the following is FALSE?
D and E are points on the sides AB and AC, respectively, of ΔABC such that DE is parallel to BC and AD ∶ DB = 7 ∶ 9. If CD and BE intersect each other at F. then find the ratio of areas of ΔDEF and ΔCBF.