To find the measure of each exterior angle of a regular octagon, we use the properties of polygons.
Identify the type of polygon. The question refers to a regular octagon.
Determine the number of sides ($n$) for the polygon. An octagon has $n = 8$ sides.
Use the formula for calculating each exterior angle of a regular polygon:
Exterior Angle = $\frac{\text{Sum of Exterior Angles}}{n}$
Exterior Angle = $\frac{360^\circ}{n}$
Substitute the value of $n$ for an octagon into the formula:
Exterior Angle = $\frac{360^\circ}{8}$
Calculate the result:
Exterior Angle = $45^\circ$
Therefore, the measure of each exterior angle of a regular octagon is $45^\circ$. This matches Option A.
If the angles of a triangle are in the ratio of 2:3:4, then the difference of the measure of greatest angle and smallest angle is
In ΔABC, ∠A = 90°, AD ┴ BC and AD = BD = 2 cm. The length of CD is
How many lines of symmetry does a rectangle have?
The number of diagonals in each face a cube is
Which of the following is/are the geometric figures with the line of symmetry?
I. Rectangle
II. Isosceles triangle