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Question

Direction: Read the following information and answer the four items that follow:

Let the distribution of the number of scooters of companies X and Y sold by 5 showrooms (A, B, C, D and E) in a certain year be denoted S1 and the distribution of the number of scooters of only company X sold by the five showrooms in the same year be denoted by S2.

Showroom

A

B

C

D

E

Total number of

scooters sold

S1 (in%)

19

21

15

33

12

6400

S2 (in%)

24

18

20

30

8

3000

What is the average number of scooters of company Y sold by the showrooms A, C and E?

This question was previously asked in
CDS I 2019 Elementary Mathematics Previous Year Paper (03-Feb-2019)
The correct answer is \(461\frac{1}{3}\)

Understanding the Scooter Sales Data

The problem provides data on the distribution of scooter sales from two companies, X and Y, across five showrooms (A, B, C, D, and E). Distribution S1 represents the total number of scooters sold by both companies combined (X + Y), and distribution S2 represents the number of scooters sold by company X only. Both distributions are given as percentages of their respective totals.

To find the number of scooters of company Y sold by a specific showroom, we need to subtract the number of scooters of company X (from S2) from the total number of scooters (from S1) for that showroom.

Data Analysis from the Table

The table provides the percentage distribution for S1 (Total X+Y scooters) and S2 (Only X scooters) across the five showrooms. The total number of scooters for S1 is 6400, and for S2 is 3000.

Showroom S1 (in %) S2 (in %)
A 19 24
B 21 18
C 15 20
D 33 30
E 12 8
Total number of scooters sold 6400 3000

Calculating Scooters Sold by Company Y for Showrooms A, C, and E

We need to find the number of scooters sold by company Y in showrooms A, C, and E. This can be calculated for each showroom as follows:

Number of Y scooters = (Percentage in S1 / 100) * Total S1 scooters - (Percentage in S2 / 100) * Total S2 scooters

Showroom A:

  • Total scooters (S1) in A = \( \frac{19}{100} \times 6400 \)
  • Total scooters (S1) in A = \( 0.19 \times 6400 = 1216 \)
  • Scooters of company X (S2) in A = \( \frac{24}{100} \times 3000 \)
  • Scooters of company X (S2) in A = \( 0.24 \times 3000 = 720 \)
  • Scooters of company Y in A = \( 1216 - 720 = 496 \)

Showroom C:

  • Total scooters (S1) in C = \( \frac{15}{100} \times 6400 \)
  • Total scooters (S1) in C = \( 0.15 \times 6400 = 960 \)
  • Scooters of company X (S2) in C = \( \frac{20}{100} \times 3000 \)
  • Scooters of company X (S2) in C = \( 0.20 \times 3000 = 600 \)
  • Scooters of company Y in C = \( 960 - 600 = 360 \)

Showroom E:

  • Total scooters (S1) in E = \( \frac{12}{100} \times 6400 \)
  • Total scooters (S1) in E = \( 0.12 \times 6400 = 768 \)
  • Scooters of company X (S2) in E = \( \frac{8}{100} \times 3000 \)
  • Scooters of company X (S2) in E = \( 0.08 \times 3000 = 240 \)
  • Scooters of company Y in E = \( 768 - 240 = 528 \)

Calculating the Average Number of Y Scooters

Now we have the number of scooters of company Y sold by showrooms A, C, and E. To find the average, we sum these numbers and divide by 3 (the number of showrooms).

  • Total Y scooters from A, C, and E = \( 496 + 360 + 528 = 1384 \)
  • Average Y scooters = \( \frac{1384}{3} \)
  • Average Y scooters = \( 461.333... \)

The average can be expressed as a mixed fraction:

  • \( \frac{1384}{3} = \frac{1383 + 1}{3} = \frac{1383}{3} + \frac{1}{3} = 461 + \frac{1}{3} = 461\frac{1}{3} \)

Conclusion

The average number of scooters of company Y sold by the showrooms A, C, and E is \( 461\frac{1}{3} \).

Revision Table: Key Calculations

Showroom S1 Value (Total) S2 Value (Only X) Y Scooters (S1 - S2)
A 1216 720 496
C 960 600 360
E 768 240 528
Sum (A, C, E) - - 1384
Average (Sum / 3) - - \( \frac{1384}{3} = 461\frac{1}{3} \)

Additional Information: Percentage and Average Concepts

Understanding Percentages: A percentage represents a part out of a hundred. To calculate a percentage of a total number, you convert the percentage to a decimal (by dividing by 100) and multiply it by the total. For example, 19% of 6400 is \( \frac{19}{100} \times 6400 \).

Calculating Averages: The average (or mean) of a set of numbers is found by summing all the numbers in the set and then dividing the sum by the count of numbers in the set. In this case, we summed the number of Y scooters from three showrooms (A, C, E) and divided by 3.

This problem combines percentage calculations with the concept of finding an average, which is common in data interpretation questions.

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Important Questions from Tabulation

  1. Table shows income (in Rs.) received by 4 employees of a company during the month of December 2020 and all their income sources.

    Source

    Amit

    Suresh

    Nitin

    Varun

    Salary

    35000

    38000

    29000

    42000

    Arrears

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    6300

    5000

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    1000

    1100

    1000

    1240

    Overtime

    1800

    1950

    1400

    1500


    By what percent are the Arrears of Amit and Suresh taken together less than the Arrears of Nitin and Varun taken together?
  2. The table given below shows the GDP of two countries in different five years.

    Country
    YearsAB
    Y1175285
    Y2200300
    Y3150125
    Y47585
    Y55095

    K1 = The value of average GDP of country A in all the 5 years.

    K2 = The value of average GDP of country B in all the 5 years.

    What is the value of (K1 + K2)?

  3. Study the Table Properly and answer by interpreting the data

    The table shows the percentage population of five districts in a state below poverty line and the proportion of males and females.

    DistrictPercentage of population
    below poverty level
    Proportion of Male and Female 
    Below poverty line (M:F)Above poverty Line (M:F)
    D1152 : 33 : 2
    D2183 : 47 : 5
    D3202 : 53 : 4
    D4255 : 24 : 3
    D5123 : 72 : 7

    If the total population in the district D3 is 40,000, then what is the population of below poverty line in the district D3, ?

  4. The table given below shows the marks obtained by 4 students in 5 subjects. The maximum marks of each subject is 100.

    Subjects

    Students

    P1

    P2

    P3

    P4

    S1

    89

    100

    92

    91

    S2

    62

    52

    72

    37

    S3

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    55

    70

    65

    S4

    76

    85

    76

    58

    S5

    85

    70

    66

    62

    What is the total percent marks of P4?

  5. The data given below shows the number of people who have saved a certain amount of money.

    Savings

    (in Rs.)

    Number of people

    5

    1

    15

    3

    20

    4

    25

    2

    30

    1

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