What is the angle of elevation of the sun when the shadow of a 9-m high pole is \(3\sqrt 3 \) m long?
60°
This problem asks us to find the angle at which the sun's rays hit the ground, creating a shadow of a known length from a pole of a known height. This situation forms a right-angled triangle, where:
In a right-angled triangle, the relationship between the opposite side, the adjacent side, and the angle is given by the tangent function. The formula is:
\(\tan(\theta) = \frac{\text{Opposite Side}}{\text{Adjacent Side}}\)
Where:
Now, let's substitute the given values into the tangent formula:
\(\tan(\theta) = \frac{9 \text{ m}}{3\sqrt 3 \text{ m}}\)
We can simplify this expression:
\(\tan(\theta) = \frac{9}{3\sqrt 3}\)
First, divide the numerator and the denominator by 3:
\(\tan(\theta) = \frac{3}{\sqrt 3}\)
To make the denominator a rational number, we can multiply both the numerator and the denominator by \(\sqrt 3\):
\(\tan(\theta) = \frac{3}{\sqrt 3} \times \frac{\sqrt 3}{\sqrt 3}\)
\(\tan(\theta) = \frac{3\sqrt 3}{3}\)
Now, cancel out the 3 from the numerator and the denominator:
\(\tan(\theta) = \sqrt 3\)
We need to find the angle \(\theta\) whose tangent is \(\sqrt 3\). We recall the standard trigonometric values for common angles. The tangent of 60° is \(\sqrt 3\).
So,
\(\theta = \tan^{-1}(\sqrt 3)\)
\(\theta = 60^\circ\)
Therefore, the angle of elevation of the sun is 60°.
Here's a quick overview of the steps taken to find the angle of elevation:
| Angle (\(\theta\)) | \(\sin(\theta)\) | \(\cos(\theta)\) | \(\tan(\theta)\) |
|---|---|---|---|
| 0° | 0 | 1 | 0 |
| 30° | \(\frac{1}{2}\) | \(\frac{\sqrt 3}{2}\) | \(\frac{1}{\sqrt 3}\) |
| 45° | \(\frac{1}{\sqrt 2}\) | \(\frac{1}{\sqrt 2}\) | 1 |
| 60° | \(\frac{\sqrt 3}{2}\) | \(\frac{1}{2}\) | \(\sqrt 3\) |
| 90° | 1 | 0 | Undefined |
The angle of elevation is the angle measured upwards from the horizontal line of sight to an object above the observer. In contrast, the angle of depression is the angle measured downwards from the horizontal line of sight to an object below the observer.
Both angles are crucial in trigonometry and are used extensively in surveying, navigation, physics, and engineering to solve problems involving heights, distances, and angles.
When dealing with problems like the height of a building or pole and its shadow, the angle of elevation of the sun is typically the angle formed at the ground level.
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