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Question

A vertical pole and a vertical tower are on the same level ground in such a way that, from the top of the pole, the angle of elevation of the top of the tower is 60° and the angle of depression of the bottom of the tower is 30°. If the height of the pole is 24 m, then find the height of the tower (in m).

This question was previously asked in
SSC CGL 2020 (Tier-2) Statistics Previous Year Paper 3 (28-Jan-2022)
The correct answer is

96

Calculating Tower Height Using Angle of Elevation and Depression

This problem involves using trigonometry, specifically the tangent function, to find the height of a tower given the height of a pole and the angles of elevation and depression from the top of the pole to the top and bottom of the tower, respectively.

Understanding the Geometry

Let's visualize the scenario:

  • Let PQ be the vertical pole with height 24 m. P is the top, and Q is the bottom.
  • Let TB be the vertical tower. T is the top, and B is the bottom.
  • The pole and tower are on the same level ground, so Q and B are on the ground.
  • Draw a horizontal line from the top of the pole P, meeting the tower at point R.
  • The angle of elevation of the top of the tower (T) from P is ∠TPR = 60°.
  • The angle of depression of the bottom of the tower (B) from P is ∠RPB = 30°.
  • The figure PQBR forms a rectangle, where PQ is parallel to RB and PR is parallel to QB.
  • Therefore, PQ = RB = 24 m and PR = QB. PR is the horizontal distance between the pole and the tower.
  • The height of the tower is TB = TR + RB.

Applying Trigonometry to Find Distances

We can use the tangent function ($\tan \theta = \frac{\text{Opposite}}{\text{Adjacent}}$) in the right triangles formed.

Step 1: Find the horizontal distance PR (or QB)

Consider the right triangle ▵PBR. The angle of depression from P to B is 30°. In this triangle, RB is the side opposite to the angle ∠RPB (which is 30°), and PR is the side adjacent to this angle. We know RB = 24 m (height of the pole).

Using tangent:

$$ \tan(30^\circ) = \frac{\text{Opposite side}}{\text{Adjacent side}} = \frac{RB}{PR} $$
$$ \tan(30^\circ) = \frac{24}{PR} $$

We know that $\tan(30^\circ) = \frac{1}{\sqrt3}$.

$$ \frac{1}{\sqrt3} = \frac{24}{PR} $$

Solving for PR:

$$ PR = 24 \times \sqrt3 = 24\sqrt3 \text{ m} $$

So, the horizontal distance between the pole and the tower is $24\sqrt3$ m.

Step 2: Find the height TR

Now consider the right triangle ▵PTR. The angle of elevation from P to T is 60°. In this triangle, TR is the side opposite to ∠TPR (which is 60°), and PR is the side adjacent to this angle. We just found PR = $24\sqrt3$ m.

Using tangent:

$$ \tan(60^\circ) = \frac{\text{Opposite side}}{\text{Adjacent side}} = \frac{TR}{PR} $$
$$ \tan(60^\circ) = \frac{TR}{24\sqrt3} $$

We know that $\tan(60^\circ) = \sqrt3$.

$$ \sqrt3 = \frac{TR}{24\sqrt3} $$

Solving for TR:

$$ TR = \sqrt3 \times 24\sqrt3 = 24 \times (\sqrt3 \times \sqrt3) = 24 \times 3 = 72 \text{ m} $$

Step 3: Calculate the total height of the tower

The total height of the tower TB is the sum of TR and RB.

$$ \text{Height of tower (TB)} = TR + RB $$
$$ \text{Height of tower (TB)} = 72 \text{ m} + 24 \text{ m} $$
$$ \text{Height of tower (TB)} = 96 \text{ m} $$

Summary of Calculations

Triangle Angle Opposite Side Adjacent Side Tangent Equation Calculated Value
▵PBR ∠RPB = 30° RB = 24 m PR $\tan(30^\circ) = \frac{24}{PR}$ PR = $24\sqrt3$ m
▵PTR ∠TPR = 60° TR PR = $24\sqrt3$ m $\tan(60^\circ) = \frac{TR}{24\sqrt3}$ TR = 72 m

Total Tower Height = TR + RB = 72 m + 24 m = 96 m.

Thus, the height of the tower is 96 m.

Revision Table: Key Concepts

Concept Description Relevance to Problem
Angle of Elevation The angle between the horizontal line of sight and the line of sight upwards to an object. Used to find the upper part of the tower's height (TR).
Angle of Depression The angle between the horizontal line of sight and the line of sight downwards to an object. Used to find the horizontal distance between the pole and tower (PR) using the pole's height (RB).
Trigonometric Ratios Relationships between angles and sides of right triangles (SOH CAH TOA). Tangent ($\tan$) is used as it relates the opposite and adjacent sides.
Right Triangle A triangle with one angle equal to 90 degrees. ▵PBR and ▵PTR are right triangles formed by the horizontal line and vertical objects.

Additional Information: Angles and Heights

Problems involving angles of elevation and depression often require drawing a clear diagram and identifying the right triangles. The horizontal line of sight from the observer's position is crucial for defining these angles correctly. The angle of depression from point P to point B is equal to the angle of elevation from point B to point P (alternate interior angles if the horizontal line is parallel to the ground).

In this specific problem:

  • The height of the pole gives us the height of the rectangle part below the horizontal line from the top of the pole.
  • The angle of depression helps find the horizontal distance using the pole's height.
  • The angle of elevation helps find the remaining height of the tower above the horizontal line using the horizontal distance.
  • The total height of the taller object (tower) is the sum of the height equal to the shorter object (pole) and the height calculated using the angle of elevation.
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Similar Questions

  1. A person standing at a distance looks at a building having a height of 1000 metres. The angle between the top of the building and the ground is 30°. At what approximate distance (in metres) is the person standing away from the building.

  2. Two ships are on the opposite of a light house such that all three of them are collinear. The angles of depression of the two ships from the top of the light house are 30° and 60°. If the ships are 230√3 m apart, then find the height of the light house (in m).

  3. The angle of elevation of the top of a building at a distance of 70 m from its foot on a horizontal plane is found to be 60°. Find the height of the building.

  4. From the top of an upright pole 17.75 m high, the angle of elevation of the top of an upright tower was 60⁰. If the tower was 57.75 m tall, how far away (in m) from the foot of the pole was the foot of the tower?

  5. From the top of an upright pole 24√3 feet high, the angle of elevation of the top of an upright tower was 60°. If the foot of the pole was 60 feet away from the foot of the tower, what tall (in feet) was the tower?

  6. The angle of elevation of the top of a tower from the top of a building whose height is 680 m is 45° and the angle of elevation of the top of same tower from the foot of the same building is 60°. What is the height (in m) of the tower?

  7. The angle of elevation of the top of an unfinished tower at a point distant 78 m from its base is 30°. How much higher must the tower be raised (in m) so that the angle of elevation of the top of the finished tower at the same point will be 60º?
  8. A kite is attached to a string. Find the length of the string (in m) when the height of the kite is 90 m and the string makes an angle of 30° with the ground.

  9. The angle of elevation of the top of a tall building from the points M and N at the distances of 72 m and 128 m, respectilvely, from the base of the building and in the same straight line with it, are complementary. The height of the building (in m) is:

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Important Questions from Heights and Distances

  1. Two ships are sailing in the sea on the two sides of a lighthouse. The angles of elevation of the top of the lighthouse as observed from the ships are 45 ° and 60° respectively. If the lighthouse is 81 m high, then the distance between two ships is:

  2. The horizontal distance between two towers is 40√3 m. The angle of depression of the top of the first tower when seen from the top of the second tower is 30°. If the height of the second tower is 130 m, find the height of the first tower.

  3. The angle of elevation of a ladder leaning against a house is 60° and the foot of the ladder is 6.5 metres from the house. The length of the ladder is

  4. A kite is flying at a height of 50 m. If the length of the string is 100 m then the inclination of the string to the horizontal ground in degree measures is:

    A. 90

    B. 45

    C. 60

    D. 30

  5. Two poles of the height 15 m and 20 m stand vertically upright on a plane ground. If the distance between their feet is 12 m, find the distance between their tops.

    A. 11 m

    B. 12 m

    C. 13 m

    D. 14 m

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