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Question

A vertical pole and a vertical tower are on the same level ground in such a way that, from the top of the pole, the angle of elevation of the top of the tower is 60° and the angle of depression of the bottom of the tower is 30°. If the height of the pole is 24 m, then find the height of the tower (in m).

This question was previously asked in
SSC CGL 2020 (Tier-2) Statistics Previous Year Paper 3 (28-Jan-2022)
The correct answer is

96

Calculating Tower Height Using Angle of Elevation and Depression

This problem involves using trigonometry, specifically the tangent function, to find the height of a tower given the height of a pole and the angles of elevation and depression from the top of the pole to the top and bottom of the tower, respectively.

Understanding the Geometry

Let's visualize the scenario:

  • Let PQ be the vertical pole with height 24 m. P is the top, and Q is the bottom.
  • Let TB be the vertical tower. T is the top, and B is the bottom.
  • The pole and tower are on the same level ground, so Q and B are on the ground.
  • Draw a horizontal line from the top of the pole P, meeting the tower at point R.
  • The angle of elevation of the top of the tower (T) from P is ∠TPR = 60°.
  • The angle of depression of the bottom of the tower (B) from P is ∠RPB = 30°.
  • The figure PQBR forms a rectangle, where PQ is parallel to RB and PR is parallel to QB.
  • Therefore, PQ = RB = 24 m and PR = QB. PR is the horizontal distance between the pole and the tower.
  • The height of the tower is TB = TR + RB.

Applying Trigonometry to Find Distances

We can use the tangent function ($\tan \theta = \frac{\text{Opposite}}{\text{Adjacent}}$) in the right triangles formed.

Step 1: Find the horizontal distance PR (or QB)

Consider the right triangle ▵PBR. The angle of depression from P to B is 30°. In this triangle, RB is the side opposite to the angle ∠RPB (which is 30°), and PR is the side adjacent to this angle. We know RB = 24 m (height of the pole).

Using tangent:

$$ \tan(30^\circ) = \frac{\text{Opposite side}}{\text{Adjacent side}} = \frac{RB}{PR} $$
$$ \tan(30^\circ) = \frac{24}{PR} $$

We know that $\tan(30^\circ) = \frac{1}{\sqrt3}$.

$$ \frac{1}{\sqrt3} = \frac{24}{PR} $$

Solving for PR:

$$ PR = 24 \times \sqrt3 = 24\sqrt3 \text{ m} $$

So, the horizontal distance between the pole and the tower is $24\sqrt3$ m.

Step 2: Find the height TR

Now consider the right triangle ▵PTR. The angle of elevation from P to T is 60°. In this triangle, TR is the side opposite to ∠TPR (which is 60°), and PR is the side adjacent to this angle. We just found PR = $24\sqrt3$ m.

Using tangent:

$$ \tan(60^\circ) = \frac{\text{Opposite side}}{\text{Adjacent side}} = \frac{TR}{PR} $$
$$ \tan(60^\circ) = \frac{TR}{24\sqrt3} $$

We know that $\tan(60^\circ) = \sqrt3$.

$$ \sqrt3 = \frac{TR}{24\sqrt3} $$

Solving for TR:

$$ TR = \sqrt3 \times 24\sqrt3 = 24 \times (\sqrt3 \times \sqrt3) = 24 \times 3 = 72 \text{ m} $$

Step 3: Calculate the total height of the tower

The total height of the tower TB is the sum of TR and RB.

$$ \text{Height of tower (TB)} = TR + RB $$
$$ \text{Height of tower (TB)} = 72 \text{ m} + 24 \text{ m} $$
$$ \text{Height of tower (TB)} = 96 \text{ m} $$

Summary of Calculations

Triangle Angle Opposite Side Adjacent Side Tangent Equation Calculated Value
▵PBR ∠RPB = 30° RB = 24 m PR $\tan(30^\circ) = \frac{24}{PR}$ PR = $24\sqrt3$ m
▵PTR ∠TPR = 60° TR PR = $24\sqrt3$ m $\tan(60^\circ) = \frac{TR}{24\sqrt3}$ TR = 72 m

Total Tower Height = TR + RB = 72 m + 24 m = 96 m.

Thus, the height of the tower is 96 m.

Revision Table: Key Concepts

Concept Description Relevance to Problem
Angle of Elevation The angle between the horizontal line of sight and the line of sight upwards to an object. Used to find the upper part of the tower's height (TR).
Angle of Depression The angle between the horizontal line of sight and the line of sight downwards to an object. Used to find the horizontal distance between the pole and tower (PR) using the pole's height (RB).
Trigonometric Ratios Relationships between angles and sides of right triangles (SOH CAH TOA). Tangent ($\tan$) is used as it relates the opposite and adjacent sides.
Right Triangle A triangle with one angle equal to 90 degrees. ▵PBR and ▵PTR are right triangles formed by the horizontal line and vertical objects.

Additional Information: Angles and Heights

Problems involving angles of elevation and depression often require drawing a clear diagram and identifying the right triangles. The horizontal line of sight from the observer's position is crucial for defining these angles correctly. The angle of depression from point P to point B is equal to the angle of elevation from point B to point P (alternate interior angles if the horizontal line is parallel to the ground).

In this specific problem:

  • The height of the pole gives us the height of the rectangle part below the horizontal line from the top of the pole.
  • The angle of depression helps find the horizontal distance using the pole's height.
  • The angle of elevation helps find the remaining height of the tower above the horizontal line using the horizontal distance.
  • The total height of the taller object (tower) is the sum of the height equal to the shorter object (pole) and the height calculated using the angle of elevation.
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Similar Questions

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  3. A pole 23 m long reaches a window which is 3 \(\sqrt5\) m above the ground on one side of a street. Keeping its foot at the same point, the pole is turned to the other side of the street to reach a window 4 \(\sqrt15\)  m high. What is the width (in m) of the street?
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Important Questions from Heights and Distances

  1. A peacock sitting at the top of a 3 meter high pole saw a snake approaching towards pole at a distance three times of the height of the pole. Then it jumping from pole will catch the snake at what distance from the pole if both are running with same speed ?

  2. The foot of a ladder 25 m long is 7 m from the base of the building. If the top of the ladder slips by 4 m, then by how much distance will the foot of the ladder slide?

  3. Two hotels stand 25 m apart. One of them is 70 m high and the angle of depression of the top of other as observed from the top of this hotel is 45°. Height of the other hotel is:

  4. If the angles of elevation of a balloon from two consecutive kilometer-stones along a straight road are 30° and 60° respectively, then the height of the balloon above the ground will be:

  5. The angle of elevation of the top of a tower from a point 20 m away from its base is 45 °. What is the height of the tower?

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