A vertical pole and a vertical tower are on the same level ground in such a way that, from the top of the pole, the angle of elevation of the top of the tower is 60° and the angle of depression of the bottom of the tower is 30°. If the height of the pole is 24 m, then find the height of the tower (in m).
96
This problem involves using trigonometry, specifically the tangent function, to find the height of a tower given the height of a pole and the angles of elevation and depression from the top of the pole to the top and bottom of the tower, respectively.
Let's visualize the scenario:
We can use the tangent function ($\tan \theta = \frac{\text{Opposite}}{\text{Adjacent}}$) in the right triangles formed.
Consider the right triangle ▵PBR. The angle of depression from P to B is 30°. In this triangle, RB is the side opposite to the angle ∠RPB (which is 30°), and PR is the side adjacent to this angle. We know RB = 24 m (height of the pole).
Using tangent:
We know that $\tan(30^\circ) = \frac{1}{\sqrt3}$.
Solving for PR:
So, the horizontal distance between the pole and the tower is $24\sqrt3$ m.
Now consider the right triangle ▵PTR. The angle of elevation from P to T is 60°. In this triangle, TR is the side opposite to ∠TPR (which is 60°), and PR is the side adjacent to this angle. We just found PR = $24\sqrt3$ m.
Using tangent:
We know that $\tan(60^\circ) = \sqrt3$.
Solving for TR:
The total height of the tower TB is the sum of TR and RB.
| Triangle | Angle | Opposite Side | Adjacent Side | Tangent Equation | Calculated Value |
|---|---|---|---|---|---|
| ▵PBR | ∠RPB = 30° | RB = 24 m | PR | $\tan(30^\circ) = \frac{24}{PR}$ | PR = $24\sqrt3$ m |
| ▵PTR | ∠TPR = 60° | TR | PR = $24\sqrt3$ m | $\tan(60^\circ) = \frac{TR}{24\sqrt3}$ | TR = 72 m |
Total Tower Height = TR + RB = 72 m + 24 m = 96 m.
Thus, the height of the tower is 96 m.
| Concept | Description | Relevance to Problem |
|---|---|---|
| Angle of Elevation | The angle between the horizontal line of sight and the line of sight upwards to an object. | Used to find the upper part of the tower's height (TR). |
| Angle of Depression | The angle between the horizontal line of sight and the line of sight downwards to an object. | Used to find the horizontal distance between the pole and tower (PR) using the pole's height (RB). |
| Trigonometric Ratios | Relationships between angles and sides of right triangles (SOH CAH TOA). | Tangent ($\tan$) is used as it relates the opposite and adjacent sides. |
| Right Triangle | A triangle with one angle equal to 90 degrees. | ▵PBR and ▵PTR are right triangles formed by the horizontal line and vertical objects. |
Problems involving angles of elevation and depression often require drawing a clear diagram and identifying the right triangles. The horizontal line of sight from the observer's position is crucial for defining these angles correctly. The angle of depression from point P to point B is equal to the angle of elevation from point B to point P (alternate interior angles if the horizontal line is parallel to the ground).
In this specific problem:
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