What is the angle between the hour hand and the minute hand at quarter to five?
127.5°
Understanding how to calculate the angle between the hour and minute hands of a clock is a common type of question. We need to find the angle at a specific time: quarter to five. Quarter to five means the time is 4:45.
To solve this, we need to figure out the position of both the hour hand and the minute hand relative to the 12 o'clock mark (which we consider 0 degrees) at 4:45.
At 4:45, the minute hand is exactly on the 9. The angle is calculated based on the minutes past 12:
Angle of minute hand = Minutes × \(6^\circ\)/minute
Angle of minute hand = \(45 \times 6^\circ = 270^\circ\) from the 12 o'clock position.
At 4:45, the hour hand is not exactly on the 4. It has moved past the 4 because of the 45 minutes that have passed since 4:00. We calculate its position based on the total time past 12 o'clock in hours.
4 hours and 45 minutes is equivalent to 4 + \(45/60\) hours = 4 + 0.75 hours = 4.75 hours.
Angle of hour hand = (Hours past 12) × \(30^\circ\)/hour
Angle of hour hand = \(4.75 \times 30^\circ = 142.5^\circ\) from the 12 o'clock position.
The angle between the hands is the absolute difference between their positions:
Angle = \(|\)Angle of minute hand - Angle of hour hand\(|\)
Angle = \(|270^\circ - 142.5^\circ|\)
Angle = \(|127.5^\circ| = 127.5^\circ\)
Sometimes, the angle calculated this way might be greater than 180 degrees. In such cases, the smaller angle is \(360^\circ\) minus the calculated angle. However, \(127.5^\circ\) is less than 180 degrees, so this is the angle we are looking for.
| Hand | Time Relative to 12 | Calculation | Angle from 12 |
|---|---|---|---|
| Minute Hand | 45 minutes | \(45 \times 6^\circ\) | \(270^\circ\) |
| Hour Hand | 4 hours 45 minutes (4.75 hours) | \(4.75 \times 30^\circ\) | \(142.5^\circ\) |
Difference in angles = \(|270^\circ - 142.5^\circ| = 127.5^\circ\).
The angle between the hour hand and the minute hand at quarter to five (4:45) is \(127.5^\circ\).
| Hand | Speed | Position Formula (from 12) |
|---|---|---|
| Minute Hand | \(6^\circ\)/minute | Minutes × \(6^\circ\) |
| Hour Hand | \(0.5^\circ\)/minute or \(30^\circ\)/hour |
(Hours + Minutes/60) × \(30^\circ\) or (Hours × 30°) + (Minutes × 0.5°) |
Angle between hands = \(|\)Hour Hand Angle - Minute Hand Angle\(|\). If the result is > 180°, subtract from 360°.
Clock angle problems involve calculating the angle between the hands of an analog clock. The key is understanding the relative speeds of the hour and minute hands. The minute hand moves much faster than the hour hand.
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