11.5°
Understanding how the hour and minute hands move is key to solving clock angle problems. The hands of a clock move at constant speeds relative to the 12 o'clock position.
The minute hand completes a full circle (360 degrees) in 60 minutes. The hour hand completes a full circle (360 degrees) in 12 hours.
| Hand | Movement in 1 Hour | Movement in 1 Minute |
|---|---|---|
| Minute Hand | \(360^\circ\) | \(360^\circ / 60 \text{ minutes} = 6^\circ \text{ per minute}\) |
| Hour Hand | \(360^\circ / 12 \text{ hours} = 30^\circ \text{ per hour}\) | \(30^\circ / 60 \text{ minutes} = 0.5^\circ \text{ per minute}\) |
We need to find the angle of each hand relative to the 12 o'clock position at 2:13 p.m.
At 2:13 p.m., the minute hand is exactly at the 13-minute mark. Since the minute hand moves \(6^\circ\) per minute:
Angle of Minute Hand = \(13 \text{ minutes} \times 6^\circ/\text{minute}\)
Angle of Minute Hand = \(78^\circ\)
At 2:13 p.m., the hour hand is past the 2 o'clock mark. It has moved for 2 full hours and an additional 13 minutes from the 12 o'clock position.
The hour hand moves \(30^\circ\) per hour and \(0.5^\circ\) per minute.
Angle due to 2 hours = \(2 \text{ hours} \times 30^\circ/\text{hour} = 60^\circ\)
Angle due to 13 minutes = \(13 \text{ minutes} \times 0.5^\circ/\text{minute} = 6.5^\circ\)
Total Angle of Hour Hand = Angle due to hours + Angle due to minutes
Total Angle of Hour Hand = \(60^\circ + 6.5^\circ = 66.5^\circ\)
To find the angle between the hands, we calculate the absolute difference between their angles from the 12 o'clock mark:
Difference = \(|\text{Angle of Minute Hand} - \text{Angle of Hour Hand}|\)
Difference = \(|78^\circ - 66.5^\circ|\)
Difference = \(|11.5^\circ|\)
Difference = \(11.5^\circ\)
The calculated difference is \(11.5^\circ\). Since this is less than \(180^\circ\), it is already the acute angle between the hands.
Thus, the acute angle between the hour-hand and the minute-hand at 2:13 p.m. is \(11.5^\circ\).
| Hand | Speed | Angle at H hours, M minutes from 12 |
|---|---|---|
| Minute Hand | \(6^\circ/\text{minute}\) | \(M \times 6^\circ\) |
| Hour Hand | \(0.5^\circ/\text{minute}\) (or \(30^\circ/\text{hour}\)) | \( (H \times 30^\circ) + (M \times 0.5^\circ) \) |
Angle between hands \( = |(H \times 30 + M \times 0.5) - (M \times 6)|^\circ \)
Angle between hands \( = |30H + 0.5M - 6M|^\circ \)
Angle between hands \( = |30H - 5.5M|^\circ \)
Using the formula for H=2, M=13:
Angle \( = |30 \times 2 - 5.5 \times 13|^\circ \)
Angle \( = |60 - 71.5|^\circ \)
Angle \( = |-11.5|^\circ \)
Angle \( = 11.5^\circ \)
If the result is greater than \(180^\circ\), subtract it from \(360^\circ\) to get the acute angle.
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