What are the order and the degree respectively of the differential equation \(\rm x^2\left(\frac{d^3 y}{d x^3}\right)^2+\left(\frac{d y}{d x}\right)^4+\sin x=0\) ?
3, 2
Let's break down how to find the order and the degree of a given differential equation. The equation provided is:
\(\rm x^2\left(\frac{d^3 y}{d x^3}\right)^2+\left(\frac{d y}{d x}\right)^4+\sin x=0\)
The order of a differential equation is determined by the highest order derivative present in the equation. To find the order, you need to look at all the derivative terms and identify the highest number of times the dependent variable (y) is differentiated with respect to the independent variable (x).
In our equation, we have two derivative terms:
Comparing these, the highest order derivative is \(\frac{d^3 y}{d x^3}\), which is of order 3.
Therefore, the order of the given differential equation is 3.
The degree of a differential equation is the power of the highest order derivative, provided that the differential equation can be expressed as a polynomial in the derivatives. You need to make sure the equation is free from radicals or fractions involving derivatives. Trigonometric functions, exponentials, or logarithms of derivatives can also prevent the degree from being defined in the usual way, as they are not polynomials in the derivatives.
Our given equation is:
\(\rm x^2\left(\frac{d^3 y}{d x^3}\right)^2+\left(\frac{d y}{d x}\right)^4+\sin x=0\)
Let's examine it:
Thus, the degree of the differential equation is the power of the highest order derivative, which is 2.
Therefore, the degree of the given differential equation is 2.
Based on our analysis:
The order and degree of the differential equation are 3 and 2, respectively.
| Feature | Definition | Applied to \(\rm x^2\left(\frac{d^3 y}{d x^3}\right)^2+\left(\frac{d y}{d x}\right)^4+\sin x=0\) | Result |
|---|---|---|---|
| Order | Highest order of derivative present | Highest derivative is \(\frac{d^3 y}{d x^3}\) (order 3) | 3 |
| Degree | Power of the highest order derivative (if equation is a polynomial in derivatives) | Highest order derivative is \(\frac{d^3 y}{d x^3}\). Its power is 2. The equation is a polynomial in derivatives. | 2 |
So, the order is 3 and the degree is 2.
| Term | Meaning | Example |
|---|---|---|
| Differential Equation | An equation involving an independent variable, a dependent variable, and derivatives of the dependent variable with respect to the independent variable. | \(\frac{dy}{dx} = y + x\) |
| Order of DE | The order of the highest derivative in the equation. | In \(\frac{d^2y}{dx^2} + (\frac{dy}{dx})^3 = 0\), the highest order is 2. |
| Degree of DE | The power of the highest order derivative, provided the equation is a polynomial in derivatives. | In \(\frac{d^2y}{dx^2} + (\frac{dy}{dx})^3 = 0\), the highest order derivative is \(\frac{d^2y}{dx^2}\) with power 1. Degree is 1. In \((\frac{d^3y}{dx^3})^2 + y = 0\), highest order is 3, its power is 2. Degree is 2. |
Differential equations can be classified in several ways:
Consider the following in respect of the differential equation:
\(\frac{{{d^2}y}}{{d{x^2}}} + 2{\left( {\frac{{dy}}{{dx}}} \right)^2} + 9y = x\)
1. The degree of the differential equation is 1.
2. The order of the differential equation is 2.
Which of the above statements is/are correct?
The degree of the differential equation \(\frac{{{\rm{dy}}}}{{{\rm{dx}}}} - {\rm{x}} = {\left( {{\rm{y}} - {\rm{x}}\frac{{{\rm{dy}}}}{{{\rm{dx}}}}} \right)^{ - 4}}\) is
What is the degree of the differential equation? \(1+\left(\frac{dy}{dx}\right)^2 =\left(\frac{d^2y}{dx^2}\right)^{\frac{4}{3}}?\)
What is the order of the differential equation of all ellipses whose axes are along the coordinate axes?
What is the degree of the differential equation of all circles touching both the coordinate axes in the first quadrant?
What is the degree of the differential equation \(\frac{{{d}^{3}}y}{d{{x}^{3}}}+{{\left( \frac{dy}{dx} \right)}^{2}}-{{x}^{2}}\left( \frac{{{d}^{4}}y}{d{{x}^{4}}} \right)=0?\)
The differential equation of the family of curves y = p cos (ax) + q sin (ax), where p, q are arbitrary constants, is
The order and degree of the differential equation y 2= 4a (x – a), where ‘a’ is an arbitrary constant, are respectively
Consider the following statements :
1. The degree of the differential equation \(\frac{\text{dy}}{\text{dx}} + \cos \left(\frac{\text{dy}}{\text{dx}}\right)\) = 0 is 1.
2. The order of the differential equation \(\left(\frac{\text{d}^2\text{y}}{\text{dx}^2}\right)^3 + \cos \left(\frac{\text{dy}}{\text{dx}}\right)\) = 0 is 2.
Which of the statements given above is/are correct?
What are the order and degree, respectively, of the differential equation \({\left( {\frac{{{{\rm{d}}^3}{\rm{y}}}}{{{\rm{d}}{{\rm{x}}^3}}}} \right)^2} = {{\rm{y}}^4} + {\left( {\frac{{{\rm{dy}}}}{{{\rm{dx}}}}} \right)^5}?\)
Consider the following in respect of the differential equation:
\(\frac{{{d^2}y}}{{d{x^2}}} + 2{\left( {\frac{{dy}}{{dx}}} \right)^2} + 9y = x\)
1. The degree of the differential equation is 1.
2. The order of the differential equation is 2.
Which of the above statements is/are correct?
The partial differential equation \(\frac{{\partial u}}{{\partial t}} + u\frac{{\partial u}}{{\partial x}} = \frac{{{\partial ^2}u}}{{\partial {x^2}}}\) is a
The degree of the differential equation \({\left( {\frac{{{d^2}y}}{{d{x^2}}}} \right)^3} + {\left( {\frac{{dy}}{{dx}}} \right)^2} + \sin x\left( {\frac{{dy}}{{dx}}} \right) + y = 0\) is:
In the following partial differential equation, θ is a function of t and z, and D and K are functions of θ
\(D\left( \theta \right)\frac{{{\delta ^2}\theta }}{{\delta {z^2}}} + \frac{{\delta K\left( \theta \right)}}{{\delta z}} - \frac{{\delta \theta }}{{\delta t}} = 0\)
The above equation isThe solution of the equation \({\rm{x}}\frac{{{\rm{dy}}}}{{{\rm{dx}}}} + {\rm{y}} = 0{\rm{}}\) passing through the point (1,1) is