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Question

The degree of the differential equation \(\frac{{{\rm{dy}}}}{{{\rm{dx}}}} - {\rm{x}} = {\left( {{\rm{y}} - {\rm{x}}\frac{{{\rm{dy}}}}{{{\rm{dx}}}}} \right)^{ - 4}}\) is

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NDA II 2015 GAT Previous Year Paper (16-Dec-2015)
The correct answer is

5

Understanding the Degree of a Differential Equation

To find the degree of a differential equation, we first need to understand what order and degree mean in this context. The order of a differential equation is the order of the highest derivative appearing in the equation. The degree of a differential equation is the power of the highest order derivative, provided the equation can be written as a polynomial in the derivatives. If the equation involves radicals or negative powers of derivatives, we must first clear them to express the equation as a polynomial in its derivatives.

Analyzing the Given Differential Equation

The given differential equation is:

\(\frac{{{\rm{dy}}}}{{{\rm{dx}}}} - {\rm{x}} = {\left( {{\rm{y}} - {\rm{x}}\frac{{{\rm{dy}}}}{{{\rm{dx}}}}} \right)^{ - 4}}\)

We can see that the highest order derivative present is \(\frac{{{\rm{dy}}}}{{{\rm{dx}}}}\), which is a first-order derivative. Thus, the order of this differential equation is 1.

Simplifying to Find the Degree

The equation involves a negative power of a term containing the derivative. To find the degree, we must eliminate this negative power and express the equation as a polynomial in the derivatives. The term \({\left( {{\rm{y}} - {\rm{x}}\frac{{{\rm{dy}}}}{{{\rm{dx}}}}} \right)^{ - 4}}\) can be written as \(\frac{1}{{\left( {{\rm{y}} - {\rm{x}}\frac{{{\rm{dy}}}}{{{\rm{dx}}}}} \right)^4}}\).

So the equation becomes:

\(\frac{{{\rm{dy}}}}{{{\rm{dx}}}} - {\rm{x}} = \frac{1}{{\left( {{\rm{y}} - {\rm{x}}\frac{{{\rm{dy}}}}{{{\rm{dx}}}}} \right)^4}}\)

To clear the fraction involving the derivative term, we multiply both sides of the equation by \({\left( {{\rm{y}} - {\rm{x}}\frac{{{\rm{dy}}}}{{{\rm{dx}}}}} \right)^4}\):

\(\left( {\frac{{{\rm{dy}}}}{{{\rm{dx}}}} - {\rm{x}}} \right){\left( {{\rm{y}} - {\rm{x}}\frac{{{\rm{dy}}}}{{{\rm{dx}}}}} \right)^4} = 1\)

Determining the Highest Power of the Highest Order Derivative

The equation is now in a form where we can identify the degree. The highest order derivative is \(\frac{{{\rm{dy}}}}{{{\rm{dx}}}}\). We need to find the highest power of \(\frac{{{\rm{dy}}}}{{{\rm{dx}}}}\) in the expanded form of this equation.

Let's look at the term \({\left( {{\rm{y}} - {\rm{x}}\frac{{{\rm{dy}}}}{{{\rm{dx}}}}} \right)^4}\). When expanded using the binomial theorem, the terms will involve powers of \({\rm{y}}\) and \(-{\rm{x}}\frac{{{\rm{dy}}}}{{{\rm{dx}}}}\). The term with the highest power of \(\frac{{{\rm{dy}}}}{{{\rm{dx}}}}\) in this expansion comes from \(\left( {-{\rm{x}}\frac{{{\rm{dy}}}}{{{\rm{dx}}}}} \right)^4\), which is \((-{\rm{x}})^4 \left(\frac{{{\rm{dy}}}}{{{\rm{dx}}}}\right)^4 = {\rm{x}}^4 \left(\frac{{{\rm{dy}}}}{{{\rm{dx}}}}\right)^4\).

Now consider the entire left side of the equation: \(\left( {\frac{{{\rm{dy}}}}{{{\rm{dx}}}} - {\rm{x}}} \right){\left( {{\rm{y}} - {\rm{x}}\frac{{{\rm{dy}}}}{{{\rm{dx}}}}} \right)^4}\).

When we multiply out this expression, the term with the highest power of \(\frac{{{\rm{dy}}}}{{{\rm{dx}}}}\) will be obtained by multiplying the term with the highest power of \(\frac{{{\rm{dy}}}}{{{\rm{dx}}}}\) from each factor.

  • From the first factor \(\left( {\frac{{{\rm{dy}}}}{{{\rm{dx}}}} - {\rm{x}}} \right)\), the term with the highest power of \(\frac{{{\rm{dy}}}}{{{\rm{dx}}}}\) is \(\frac{{{\rm{dy}}}}{{{\rm{dx}}}}\) (power 1).
  • From the second factor \({\left( {{\rm{y}} - {\rm{x}}\frac{{{\rm{dy}}}}{{{\rm{dx}}}}} \right)^4}\), the term with the highest power of \(\frac{{{\rm{dy}}}}{{{\rm{dx}}}}\) is \({\rm{x}}^4 \left(\frac{{{\rm{dy}}}}{{{\rm{dx}}}}\right)^4\) (power 4).

Multiplying these terms gives: \(\left(\frac{{{\rm{dy}}}}{{{\rm{dx}}}}\right)^1 \times {\rm{x}}^4 \left(\frac{{{\rm{dy}}}}{{{\rm{dx}}}}\right)^4 = {\rm{x}}^4 \left(\frac{{{\rm{dy}}}}{{{\rm{dx}}}}\right)^{1+4} = {\rm{x}}^4 \left(\frac{{{\rm{dy}}}}{{{\rm{dx}}}}\right)^5\).

The highest power of the highest order derivative (\(\frac{{{\rm{dy}}}}{{{\rm{dx}}}}\)) in the polynomial form of the equation is 5.

Conclusion on Degree

Therefore, the degree of the given differential equation is 5.

Property Value
Given Equation \(\frac{{{\rm{dy}}}}{{{\rm{dx}}}} - {\rm{x}} = {\left( {{\rm{y}} - {\rm{x}}\frac{{{\rm{dy}}}}{{{\rm{dx}}}}} \right)^{ - 4}}\)
Simplified Form (Polynomial in derivatives) \(\left( {\frac{{{\rm{dy}}}}{{{\rm{dx}}}} - {\rm{x}}} \right){\left( {{\rm{y}} - {\rm{x}}\frac{{{\rm{dy}}}}{{{\rm{dx}}}}} \right)^4} = 1\)
Highest Order Derivative \(\frac{{{\rm{dy}}}}{{{\rm{dx}}}}\)
Order 1
Highest Power of Highest Order Derivative 5
Degree 5

Revision Table: Order and Degree of Differential Equations

Concept Definition Example
Order The order of the highest derivative in the equation. \(\frac{{{\rm{d}}^2{\rm{y}}}}{{{\rm{dx}}^2}} + \left(\frac{{{\rm{dy}}}}{{{\rm{dx}}}}\right)^3 + {\rm{y}} = 0\). Order is 2.
Degree The power of the highest order derivative after the equation is made free from radicals and fractions involving derivatives, and is written as a polynomial in derivatives. For \(\frac{{{\rm{d}}^2{\rm{y}}}}{{{\rm{dx}}^2}} + \left(\frac{{{\rm{dy}}}}{{{\rm{dx}}}}\right)^3 + {\rm{y}} = 0\), the degree is 1 (power of \(\frac{{{\rm{d}}^2{\rm{y}}}}{{{\rm{dx}}^2}}\)). For \(\left(1 + \left(\frac{{{\rm{dy}}}}{{{\rm{dx}}}}\right)^2\right)^{3/2} = \frac{{{\rm{d}}^2{\rm{y}}}}{{{\rm{dx}}^2}}\), squaring both sides gives \(\left(1 + \left(\frac{{{\rm{dy}}}}{{{\rm{dx}}}}\right)^2\right)^{3} = \left(\frac{{{\rm{d}}^2{\rm{y}}}}{{{\rm{dx}}^2}}\right)^2\). The highest order is 2 (\(\frac{{{\rm{d}}^2{\rm{y}}}}{{{\rm{dx}}^2}}\)) and its power is 2. Degree is 2.

Additional Information on Differential Equations

Differential equations are mathematical equations that relate a function with its derivatives. They are fundamental in physics, engineering, biology, economics, and many other fields because they describe how quantities change over time or space.

  • Ordinary Differential Equations (ODEs): These involve functions of a single independent variable and their derivatives. The given problem involves an ODE because \({\rm{y}}\) is a function of a single variable \({\rm{x}}\), and the equation involves only ordinary derivatives (\(\frac{{{\rm{dy}}}}{{{\rm{dx}}}}\)).
  • Partial Differential Equations (PDEs): These involve functions of multiple independent variables and their partial derivatives.
  • Linear vs. Non-linear: A differential equation is linear if the dependent variable and its derivatives appear only in the first power and are not multiplied together. Otherwise, it is non-linear. The given equation is non-linear due to the term \({\left( {{\rm{y}} - {\rm{x}}\frac{{{\rm{dy}}}}{{{\rm{dx}}}}} \right)^4}\) involving powers and products of \({\rm{y}}\) and \(\frac{{{\rm{dy}}}}{{{\rm{dx}}}}\).

Understanding the order and degree is often the first step in classifying a differential equation, which helps determine the methods suitable for solving it.

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Similar Questions

  1. Consider the following in respect of the differential equation:

    \(\frac{{{d^2}y}}{{d{x^2}}} + 2{\left( {\frac{{dy}}{{dx}}} \right)^2} + 9y = x\)

    1. The degree of the differential equation is 1.

    2. The order of the differential equation is 2.

    Which of the above statements is/are correct?

  2. What is the degree of the differential equation? \(1+\left(\frac{dy}{dx}\right)^2 =\left(\frac{d^2y}{dx^2}\right)^{\frac{4}{3}}?\)

  3. What is the order of the differential equation of all ellipses whose axes are along the coordinate axes?

  4. What is the degree of the differential equation of all circles touching both the coordinate axes in the first quadrant?

  5. What is the degree of the differential equation \(\frac{{{d}^{3}}y}{d{{x}^{3}}}+{{\left( \frac{dy}{dx} \right)}^{2}}-{{x}^{2}}\left( \frac{{{d}^{4}}y}{d{{x}^{4}}} \right)=0?\)

  6. The differential equation of the family of curves y = p cos (ax) + q sin (ax), where p, q are arbitrary constants, is

  7. The order and degree of the differential equation y 2= 4a (x – a), where ‘a’ is an arbitrary constant, are respectively

  8. Consider the following statements :

    1. The degree of the differential equation \(\frac{\text{dy}}{\text{dx}} + \cos \left(\frac{\text{dy}}{\text{dx}}\right)\)  = 0 is 1.

    2. The order of the differential equation  \(\left(\frac{\text{d}^2\text{y}}{\text{dx}^2}\right)^3 + \cos \left(\frac{\text{dy}}{\text{dx}}\right)\)  = 0 is 2.

    Which of the statements given above is/are correct?

  9. What are the order and degree, respectively, of the differential equation \({\left( {\frac{{{{\rm{d}}^3}{\rm{y}}}}{{{\rm{d}}{{\rm{x}}^3}}}} \right)^2} = {{\rm{y}}^4} + {\left( {\frac{{{\rm{dy}}}}{{{\rm{dx}}}}} \right)^5}?\)

  10. What are the order and degree respectively of the differential equation whose solution is y = cx + c 2– 3c 3/2 + 2, where c is a parameter?


Important Questions from Order and Degree of a Differential Equation

  1. Consider the following in respect of the differential equation:

    \(\frac{{{d^2}y}}{{d{x^2}}} + 2{\left( {\frac{{dy}}{{dx}}} \right)^2} + 9y = x\)

    1. The degree of the differential equation is 1.

    2. The order of the differential equation is 2.

    Which of the above statements is/are correct?

  2. The partial differential equation \(\frac{{\partial u}}{{\partial t}} + u\frac{{\partial u}}{{\partial x}} = \frac{{{\partial ^2}u}}{{\partial {x^2}}}\) is a

  3. The degree of the differential equation \({\left( {\frac{{{d^2}y}}{{d{x^2}}}} \right)^3} + {\left( {\frac{{dy}}{{dx}}} \right)^2} + \sin x\left( {\frac{{dy}}{{dx}}} \right) + y = 0\) is:

  4. In the following partial differential equation, θ is a function of t and z, and D and K are functions of θ

    \(D\left( \theta \right)\frac{{{\delta ^2}\theta }}{{\delta {z^2}}} + \frac{{\delta K\left( \theta \right)}}{{\delta z}} - \frac{{\delta \theta }}{{\delta t}} = 0\)

    The above equation is
  5. The solution of the equation \({\rm{x}}\frac{{{\rm{dy}}}}{{{\rm{dx}}}} + {\rm{y}} = 0{\rm{}}\) passing through the point (1,1) is

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