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Question

What is the degree of the differential equation? \(1+\left(\frac{dy}{dx}\right)^2 =\left(\frac{d^2y}{dx^2}\right)^{\frac{4}{3}}?\)

This question was previously asked in
NDA I 2022 GAT Previous Year Paper (10-Apr-2022)
The correct answer is

4

Understanding the Degree of a Differential Equation

The question asks for the degree of the given differential equation: \(1+\left(\frac{dy}{dx}\right)^2 =\left(\frac{d^2y}{dx^2}\right)^{\frac{4}{3}}\).

To find the degree of a differential equation, we first need to determine its order. The order of a differential equation is the order of the highest derivative present in the equation.

In the given equation, the derivatives present are \(\frac{dy}{dx}\) and \(\frac{d^2y}{dx^2}\).

  • \(\frac{dy}{dx}\) is the first derivative, so its order is 1.
  • \(\frac{d^2y}{dx^2}\) is the second derivative, so its order is 2.

The highest order derivative is \(\frac{d^2y}{dx^2}\), which has an order of 2. Therefore, the order of this differential equation is 2.

Now, to find the degree, we need to look at the power of the highest order derivative after the equation has been made free from radicals and fractions as far as derivatives are concerned.

The given equation is: \[1+\left(\frac{dy}{dx}\right)^2 =\left(\frac{d^2y}{dx^2}\right)^{\frac{4}{3}}\] Notice the term \(\left(\frac{d^2y}{dx^2}\right)^{\frac{4}{3}}\). The exponent \(\frac{4}{3}\) represents a fractional power, which is equivalent to a cube root raised to the power of 4. To eliminate this fractional power involving the derivative \(\frac{d^2y}{dx^2}\), we need to cube both sides of the entire equation.

Cubing both sides, we get: \[\left(1+\left(\frac{dy}{dx}\right)^2\right)^3 = \left(\left(\frac{d^2y}{dx^2}\right)^{\frac{4}{3}}\right)^3\]

Simplifying the right side: \[\left(\left(\frac{d^2y}{dx^2}\right)^{\frac{4}{3}}\right)^3 = \left(\frac{d^2y}{dx^2}\right)^{\frac{4}{3} \times 3} = \left(\frac{d^2y}{dx^2}\right)^4\]

So, the equation becomes: \[\left(1+\left(\frac{dy}{dx}\right)^2\right)^3 = \left(\frac{d^2y}{dx^2}\right)^4\]

In this simplified equation, which is free from fractional powers involving derivatives, the highest order derivative is still \(\frac{d^2y}{dx^2}\).

The power of this highest order derivative (\(\frac{d^2y}{dx^2}\)) is 4.

Therefore, the degree of the differential equation is 4.

Step-by-Step Determination of Degree

  1. Identify the highest order derivative in the equation. It is \(\frac{d^2y}{dx^2}\).
  2. Identify if there are any fractional or radical powers involving derivatives. Yes, the term \(\left(\frac{d^2y}{dx^2}\right)^{\frac{4}{3}}\).
  3. Raise both sides of the equation to a power that eliminates the fractional exponent for the derivative. In this case, the denominator of the exponent is 3, so cube both sides.
  4. Simplify the equation after raising to the appropriate power: \(\left(1+\left(\frac{dy}{dx}\right)^2\right)^3 = \left(\frac{d^2y}{dx^2}\right)^4\).
  5. Identify the highest order derivative again in the cleared equation. It is still \(\frac{d^2y}{dx^2}\).
  6. The power of this highest order derivative is the degree of the differential equation. The power of \(\frac{d^2y}{dx^2}\) is 4.

Thus, the degree is 4.

Concept Definition Example (from this problem)
Order of DE The order of the highest derivative in the equation. Highest derivative is \(\frac{d^2y}{dx^2}\), order is 2.
Degree of DE The power of the highest order derivative after making the equation free from fractional/radical powers involving derivatives. After cubing, power of \(\frac{d^2y}{dx^2}\) is 4. Degree is 4.

Revision Table: Key Concepts for Differential Equations

Term Description
Differential Equation An equation involving an independent variable, a dependent variable, and the derivatives of the dependent variable with respect to the independent variable.
Order The order of the highest derivative appearing in the differential equation.
Degree The power of the highest order derivative appearing in the differential equation, after the equation has been freed from radicals and fractions involving the derivatives.

Additional Information on Order and Degree

Understanding the order and degree of a differential equation is fundamental in classifying and solving them.

  • Order: This is always a positive integer. It directly tells you the 'level' of differentiation involved. A first-order equation involves only \(\frac{dy}{dx}\), a second-order involves \(\frac{d^2y}{dx^2}\) and possibly lower derivatives, and so on.
  • Degree: This is also a positive integer. However, the degree is defined only if the differential equation can be written as a polynomial in terms of the derivatives. If a differential equation contains terms like \(\sin(\frac{dy}{dx})\), \(e^{\frac{d^2y}{dx^2}}\), or \(\log(\frac{dy}{dx})\), its degree is undefined because it cannot be expressed as a polynomial in derivatives. In our case, after clearing the fractional exponent, the equation becomes a polynomial in terms of the derivatives \(\frac{dy}{dx}\) and \(\frac{d^2y}{dx^2}\), so the degree is well-defined.

Always remember to clear any fractional or radical powers that involve the derivatives before determining the degree. Only consider the power of the highest order derivative after this step.

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Similar Questions

  1. Consider the following in respect of the differential equation:

    \(\frac{{{d^2}y}}{{d{x^2}}} + 2{\left( {\frac{{dy}}{{dx}}} \right)^2} + 9y = x\)

    1. The degree of the differential equation is 1.

    2. The order of the differential equation is 2.

    Which of the above statements is/are correct?

  2. The degree of the differential equation \(\frac{{{\rm{dy}}}}{{{\rm{dx}}}} - {\rm{x}} = {\left( {{\rm{y}} - {\rm{x}}\frac{{{\rm{dy}}}}{{{\rm{dx}}}}} \right)^{ - 4}}\) is

  3. What is the order of the differential equation of all ellipses whose axes are along the coordinate axes?

  4. What is the degree of the differential equation of all circles touching both the coordinate axes in the first quadrant?

  5. What is the degree of the differential equation \(\frac{{{d}^{3}}y}{d{{x}^{3}}}+{{\left( \frac{dy}{dx} \right)}^{2}}-{{x}^{2}}\left( \frac{{{d}^{4}}y}{d{{x}^{4}}} \right)=0?\)

  6. The differential equation of the family of curves y = p cos (ax) + q sin (ax), where p, q are arbitrary constants, is

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  8. Consider the following statements :

    1. The degree of the differential equation \(\frac{\text{dy}}{\text{dx}} + \cos \left(\frac{\text{dy}}{\text{dx}}\right)\)  = 0 is 1.

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Important Questions from Order and Degree of a Differential Equation

  1. Consider the following in respect of the differential equation:

    \(\frac{{{d^2}y}}{{d{x^2}}} + 2{\left( {\frac{{dy}}{{dx}}} \right)^2} + 9y = x\)

    1. The degree of the differential equation is 1.

    2. The order of the differential equation is 2.

    Which of the above statements is/are correct?

  2. The partial differential equation \(\frac{{\partial u}}{{\partial t}} + u\frac{{\partial u}}{{\partial x}} = \frac{{{\partial ^2}u}}{{\partial {x^2}}}\) is a

  3. The degree of the differential equation \({\left( {\frac{{{d^2}y}}{{d{x^2}}}} \right)^3} + {\left( {\frac{{dy}}{{dx}}} \right)^2} + \sin x\left( {\frac{{dy}}{{dx}}} \right) + y = 0\) is:

  4. In the following partial differential equation, θ is a function of t and z, and D and K are functions of θ

    \(D\left( \theta \right)\frac{{{\delta ^2}\theta }}{{\delta {z^2}}} + \frac{{\delta K\left( \theta \right)}}{{\delta z}} - \frac{{\delta \theta }}{{\delta t}} = 0\)

    The above equation is
  5. The solution of the equation \({\rm{x}}\frac{{{\rm{dy}}}}{{{\rm{dx}}}} + {\rm{y}} = 0{\rm{}}\) passing through the point (1,1) is

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