The partial differential equation \(\frac{{\partial u}}{{\partial t}} + u\frac{{\partial u}}{{\partial x}} = \frac{{{\partial ^2}u}}{{\partial {x^2}}}\) is a
Non-linear equation of order 2
Understanding the nature of a given partial differential equation (PDE) is fundamental in mathematics. PDEs are classified based on several characteristics, primarily their linearity and order. Let's analyze the provided equation:
\[\frac{{\partial u}}{{\partial t}} + u\frac{{\partial u}}{{\partial x}} = \frac{{{\partial ^2}u}}{{\partial {x^2}}}\]
To determine if a partial differential equation is linear or non-linear, we examine how the dependent variable (in this case, \(u\)) and its derivatives appear in the equation. A PDE is considered linear if:
Conversely, if any of these conditions are not met, the PDE is non-linear.
Let's look at the terms in our given partial differential equation:
Since the term \(u\frac{{\partial u}}{{\partial x}}\) contains a product of the dependent variable \(u\) and its derivative \(\frac{{\partial u}}{{\partial x}}\), the given partial differential equation is a Non-linear equation.
The order of a partial differential equation is determined by the highest order of the partial derivatives present in the equation. Let's identify the order of each derivative term in the given partial differential equation:
Comparing the orders of all derivatives, the highest order derivative present in the partial differential equation is \(\frac{{{\partial ^2}u}}{{\partial {x^2}}}\), which is of second order. Therefore, the order of the given partial differential equation is 2.
Based on our analysis:
Thus, the partial differential equation \(\frac{{\partial u}}{{\partial t}} + u\frac{{\partial u}}{{\partial x}} = \frac{{{\partial ^2}u}}{{\partial {x^2}}}\) is a Non-linear equation of order 2.
Consider the following in respect of the differential equation:
\(\frac{{{d^2}y}}{{d{x^2}}} + 2{\left( {\frac{{dy}}{{dx}}} \right)^2} + 9y = x\)
1. The degree of the differential equation is 1.
2. The order of the differential equation is 2.
Which of the above statements is/are correct?
The degree of the differential equation \({\left( {\frac{{{d^2}y}}{{d{x^2}}}} \right)^3} + {\left( {\frac{{dy}}{{dx}}} \right)^2} + \sin x\left( {\frac{{dy}}{{dx}}} \right) + y = 0\) is:
In the following partial differential equation, θ is a function of t and z, and D and K are functions of θ
\(D\left( \theta \right)\frac{{{\delta ^2}\theta }}{{\delta {z^2}}} + \frac{{\delta K\left( \theta \right)}}{{\delta z}} - \frac{{\delta \theta }}{{\delta t}} = 0\)
The above equation isThe solution of the equation \({\rm{x}}\frac{{{\rm{dy}}}}{{{\rm{dx}}}} + {\rm{y}} = 0{\rm{}}\) passing through the point (1,1) is
The order and degree of the differential equation
\(\frac{{{d^3}y}}{{d{x^3}}} + 4\sqrt{\left[{{{{\left( {\frac{{dy}}{{dx}}} \right)}^3} + {y^2}}}\right]}= 0\;\)