A 12μF capacitor and a 4μF capacitor are connected in series. The ratio of voltages across them will be:
1:3
In a series capacitor circuit, the same charge Q appears on both capacitors.
V = Q/C, so voltage is inversely proportional to capacitance:
V12μF / V4μF = C4μF / C12μF = 4/12 = 1:3
- The smaller capacitor (4 µF) gets a larger share of the voltage.
- The larger capacitor (12 µF) gets a smaller share.
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