In a single-phase RL circuit, the RMS voltage across the supply is 100 V, the RMS current is 5 A, and the current lags the voltage by 60°. Determine the apparent power of the circuit.
500 VA
To determine the apparent power in a single-phase RL circuit, we use the formula for apparent power S given by:
S = V \times I
where:
- V is the RMS voltage across the supply.
- I is the RMS current flowing through the circuit.
From the question, we are given:
- RMS voltage, V = 100 \, \text{V}
- RMS current, I = 5 \, \text{A}
- The phase angle by which the current lags the voltage is 60^\circ. This is relevant for calculating real power but not directly needed for apparent power.
Substituting the given values into the formula for apparent power, we get:
S = 100 \, \text{V} \times 5 \, \text{A}
Thus:
S = 500 \, \text{VA}
Therefore, the apparent power of the circuit is 500 VA.
The correct answer is 500 VA.
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