Two trains, X and Y, start at the same time from Delhi and Mumbai towards each other. After meeting, train X takes 6 hours to reach Mumbai, and train Y takes 8 hours to reach Delhi. If train X's speed is 60 km/h, what is the speed of train Y?
\(30\sqrt{3}\) km/h
When two bodies start together and move towards each other, after meeting the ratio of their speeds equals \(\frac{V_X}{V_Y} = \sqrt{\frac{t_Y}{t_X}}\), where \(t_X\) and \(t_Y\) are the times taken after meeting.
Here \(t_X = 6\) hours and \(t_Y = 8\) hours, so \(\frac{V_X}{V_Y} = \sqrt{\frac{8}{6}}\).
Therefore \(V_Y = V_X \times \sqrt{\frac{6}{8}} = 60 \times \sqrt{\frac{3}{4}} = 60 \times \frac{\sqrt{3}}{2}\).
\(V_Y = 30\sqrt{3}\) km/h.
Hence, the speed of train Y is \(30\sqrt{3}\) km/h.
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Important Questions from Speed Time and Distance
The average speed of a train is 180% of the average speed of a car. The car covers a distance of 990 km in 15 hours. The time taken (in hours) by the train to cover the distance of 891 km is:
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A train is moving at 72 km/hrs. The distance covers in 15 minutes by the train is:
If Sonu is driving a car at a speed of 20 m/s, then in how much time Sonu will cover a distance of 936 km?
A person crosses a 1600 m long street in 4 min. What is his speed (in km/h)?
