The problem asks for the required speed of a horse to cover a certain distance in a new timeframe, given its initial speed and time.
First, find the distance the horse covers using the initial speed and time. The formula for distance is:
$ \text{Distance} = \text{Speed} \times \text{Time} $
Given:
Calculation:
$ \text{Distance} = 40 \, \text{km/h} \times 3 \, \text{h} = 120 \, \text{km} $
Next, calculate the speed needed to cover the same distance (120 km) in the new time ($2\frac{1}{2}$ hours).
The formula for speed is:
$ \text{Speed} = \frac{\text{Distance}}{\text{Time}} $
Given:
Calculation:
$ \text{New Speed} = \frac{120 \, \text{km}}{2.5 \, \text{h}} $
To simplify the division:
$ \text{New Speed} = \frac{120}{5/2} \, \text{km/h} = 120 \times \frac{2}{5} \, \text{km/h} = \frac{240}{5} \, \text{km/h} = 48 \, \text{km/h} $
Therefore, the horse should run at a speed of 48 km/h.
A train travelling at a speed of 72 km/hr crosses a post in 20 seconds. If it crosses another train travelling at a speed of 54 km/hr in the same direction in 1 minute 45 seconds, then the difference in length between the two trains is
Rajiv's boat can travel along the current at the 8 km/hour and against the current at the rate 6 km/hour. Find the time taken by the boat to sail 28 km in still water.
Two trains running in opposite directions cross a man standing on the platform in 25 seconds and 32 seconds respectively and they cross each other in 30 seconds. The ratio of their speed is:
A worker covers a distance of 81 km in 11 hours. He travels partly on foot at 4.5 km/h and partly on bicycle at 15 km/h. What is the distance covered on the cycle?
A car travels from a place X to place Y at an average speed of v km/hr from y to X at an average speed of 2v km/hr, again from X to y at an average speed of 3v km/hr and again from y to x at an average speed of 4v km/hr. Then the average speed of the car for the entire journey