The question asks for the total distance a cyclist covered. We are given the total time taken and the speeds for the first and second halves of the journey. The key is that the distance is divided into two equal parts.
Let the total distance be $D$ km.
The time taken for the first half ($t_1$) is:
$t_1 = \frac{\text{Distance}}{\text{Speed}} = \frac{D/2}{v_1} = \frac{D}{2 \times 7} = \frac{D}{14}$ hours.
The time taken for the second half ($t_2$) is:
$t_2 = \frac{\text{Distance}}{\text{Speed}} = \frac{D/2}{v_2} = \frac{D}{2 \times 6} = \frac{D}{12}$ hours.
The total time is the sum of the times for the two halves:
$T = t_1 + t_2$
Substitute the known values:
$13 = \frac{D}{14} + \frac{D}{12}$
To solve for $D$, find a common denominator for 14 and 12, which is 84:
$13 = \frac{6 \times D}{84} + \frac{7 \times D}{84}$
Combine the terms on the right side:
$13 = \frac{6D + 7D}{84}$
$13 = \frac{13D}{84}$
Now, solve for $D$:
$D = \frac{13 \times 84}{13}$
$D = 84$ km.
The total distance covered by the cyclist is 84 km.
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