Two plumbers, X and Y, are paid a total of ₹770 per day by their employer. If X is paid 140% of the sum paid to Y, then how much is Y paid (in ₹, rounded off to two decimal places) per day?
320.83
Let's denote the amount paid to Y as 'y'.
According to the problem, X is paid 140% of the sum paid to Y. Therefore, the amount paid to X is 1.4y.
The total amount paid to both X and Y is ₹770. We can express this as an equation:
\(y + 1.4y = 770\)
Combining the terms with 'y', we get:
\(2.4y = 770\)
Now, to find the value of y (the amount paid to Y), we divide both sides of the equation by 2.4:
\(y = \frac{770}{2.4}\)
Calculating this gives us:
\(y ≈ 320.8333\)
Rounding off to two decimal places, we find that Y is paid ₹320.83 per day.
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