Two different positions of the same dice are shown, the six faces of which are numbered 7, 8, 9, 10, 11 and 12. What will be the sum of the number 8 and the number on its opposite face ?
17
The logic followed here is :-
From the given two different cubes the adjacent sides are as shown below :
As 7 is common on both the dice, it is clear that 9, 11, 10 and 8 are adjacent to it and remaining number i.e., 12 will be opposite to it.

Opposite pairs:
9 → 8
11 → 10
7 → 12
The opposite side of "8" will be side "9".
So,The sum of the number 8 and the number on its opposite face = (8 + 9) = 17.
Hence, the correct answer is "17".
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