Two circles have radii of 8 cm and 3 cm. The distance between their centers is 15 cm. What is the length of a direct common tangent?
10√2 cm
The length of a direct common tangent between two circles with radii \(r_1\) and \(r_2\), with distance d between centers, is \(\sqrt{d^2 - (r_1-r_2)^2}\).
Substituting \(d=15\), \(r_1=8\), and \(r_2=3\): \(\sqrt{15^2 - (8-3)^2} = \sqrt{225-25} = \sqrt{200}\).
Simplifying, \(\sqrt{200} = \sqrt{100 \times 2} = 10\sqrt{2}\).
Hence, the answer is 10√2 cm.
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