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Question

In a circle with radius 5 cm, a chord is at a distance of 3 cm from the centre. The length of the chord is:

This question was previously asked in
SSC CGL 2019 (Tier 2) GS Finance & Economics Previous Year Paper (17-Nov-2020)
The correct answer is

8 cm

Finding the Length of a Chord in a Circle

This problem involves a circle, its radius, a chord, and the distance from the center to the chord. We need to find the length of the chord given the radius and the distance from the center.

Understanding the Geometry of the Circle and Chord

In any circle, a line segment drawn from the center perpendicular to a chord bisects the chord. This means it divides the chord into two equal parts. This perpendicular line segment, the radius drawn to an endpoint of the chord, and half of the chord form a right-angled triangle.

  • The hypotenuse of this right triangle is the radius of the circle.
  • One leg is the distance from the center to the chord.
  • The other leg is half the length of the chord.

Applying the Pythagorean Theorem

We can use the Pythagorean theorem in the right-angled triangle formed. The Pythagorean theorem states that in a right-angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

Let:

  • \(r\) be the radius of the circle.
  • \(d\) be the distance from the center to the chord.
  • \(x\) be half the length of the chord.

According to the Pythagorean theorem:

\(d^2 + x^2 = r^2\)

Calculating Half the Chord Length

We are given:

  • Radius, \(r = 5\) cm
  • Distance from the center to the chord, \(d = 3\) cm

Substitute these values into the Pythagorean theorem equation:

\(3^2 + x^2 = 5^2\)

\(9 + x^2 = 25\)

Subtract 9 from both sides to isolate \(x^2\):

\(x^2 = 25 - 9\)

\(x^2 = 16\)

Take the square root of both sides to find \(x\):

\(x = \sqrt{16}\)

\(x = 4\) cm

So, half the length of the chord is 4 cm.

Calculating the Full Chord Length

Since \(x\) represents half the length of the chord, the full length of the chord is \(2 \times x\).

Chord Length = \(2 \times 4\) cm

Chord Length = \(8\) cm

Summary of Calculations

Parameter Value
Radius (r) 5 cm
Distance from Center (d) 3 cm
Half Chord Length (x) 4 cm (calculated)
Full Chord Length 8 cm (calculated)

Therefore, the length of the chord is 8 cm.

Revision Table: Key Circle and Chord Concepts

Concept Description
Chord A line segment connecting two points on the circumference of a circle.
Radius A line segment from the center of the circle to any point on its circumference.
Distance from Center to Chord The length of the perpendicular segment from the center to the chord.
Perpendicular Bisector Property A perpendicular from the center to a chord bisects the chord.
Pythagorean Theorem In a right triangle, \(a^2 + b^2 = c^2\). Used here with radius as hypotenuse and distance/half chord as legs.

Additional Information: Related Circle Properties

Understanding chord properties is important in geometry. Here are a few related facts:

  • The longest chord in a circle is the diameter, which passes through the center.
  • Equal chords are equidistant from the center.
  • Chords equidistant from the center are equal in length.
  • If two chords intersect inside a circle, the products of the segments of each chord are equal (Intersecting Chords Theorem).

These properties are useful for solving various problems involving chords and circles.

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Similar Questions

  1. A chord 21 cm long is drawn in a circle of diameter 25 cm. The perpendicular distance of the chord from the centre is:

  2. The distance between the centres of two circles is 24 cm. If the radius of the two circles are 4 cm and 8 cm, then what is the sum of the lengths (in cm) of the direct common tangent and the transverse common tangent?

  3. In a circle with centre O, an arc ABC subtends an angle of 132° at the center of the circle. Chord AB is produced to point P. Then ∠CBP is equal to∶

  4. What can be the maximum number of common tangent which can be drawn to two non-intersecting circles?

  5. There are two identical circles of radius 10 cm each. If the length of the direct common tangent is 26 cm, then what is the length (in cm) of the transverse common tangent?

  6. In the figure, two circles with centres P and Q touch externally at R. Tangents AT and BT meet the common tangent TR at T. If AP = 6 cm and PT = 10 cm, then BT =?

  7. AB is a chord in the minor segment of a circle with centre O. C is a point on the minor arc (between A and B). The tangents to the circle at A and B meet at a point P. If ∠ACB = 108°, then ∠APB is equal to:

  8. AB is the chord of a circle such that AB = 10 cm. If the diameter of the circle is 20 cm, then the angle subtended by the chord at the centre is ________.

  9. Triangle ABC is circumscribed around circle D. Segments AQ, BR, and SC measure 13, 10.5, and 6 cm, respectively. The perimeter of triangle ABC is:

  10. Two circles touch each other externally. The radius of the first circle with centre O is 6 cm. The radius of the second circle with centre P is 3 cm. Find the length of their common tangent AB.


Important Questions from Circles, Chords and Tangents

  1. A chord 21 cm long is drawn in a circle of diameter 25 cm. The perpendicular distance of the chord from the centre is:

  2. AB is a chord of a circle with centre O and P is any point on the circle. If ∠APB = 112°, then what is the measure of ∠OAB ?

  3. The distance between the centres of two circles is 24 cm. If the radius of the two circles are 4 cm and 8 cm, then what is the sum of the lengths (in cm) of the direct common tangent and the transverse common tangent?

  4. An equilateral triangle ABC and a scalene triangle DBC are inscribed in a circle on same side of the arc. what is ∠BDC equal to?

  5. In a circle with centre O, an arc ABC subtends an angle of 132° at the center of the circle. Chord AB is produced to point P. Then ∠CBP is equal to∶

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