We are given a circle with a chord of length $20\text{ cm}$ and the distance from the center to this chord is $15\text{ cm}$. We need to find the approximate radius of the circle.
The radius, the distance from the center to the chord, and half the chord length form a right-angled triangle. The radius is the hypotenuse.
First, find half the length of the chord:
Half chord length $= \frac{l}{2} = \frac{20\text{ cm}}{2} = 10\text{ cm}$.
Let the radius be $r$. According to the Pythagorean theorem ($a^2 + b^2 = c^2$), where $a$ and $b$ are the legs and $c$ is the hypotenuse:
In our triangle:
So, the equation becomes:
$r^2 = d^2 + \left(\frac{l}{2}\right)^2$Substitute the values:
$r^2 = (15\text{ cm})^2 + (10\text{ cm})^2$ $r^2 = 225\text{ cm}^2 + 100\text{ cm}^2$ $r^2 = 325\text{ cm}^2$To find the radius $r$, take the square root of $325$:
$r = \sqrt{325}\text{ cm}$We know that $18^2 = 324$. Since $325$ is very close to $324$, the value of $\sqrt{325}$ will be slightly more than $18$.
$r \approx 18.03\text{ cm}$The approximate radius of the circle is $18\text{ cm}$.
In a circle, a ten cm long chord is at a distance of 12 cm from the centre of the circle. The length of the diameter of the circle (in cm) is:
Chord AB of a circle of radius 10 cm is at a distance 8 cm from the centre O. If tangents drawn at A and B intersect at P., then the length of the tangent AP (in cm) is:
A chord 21 cm long is drawn in a circle of diameter 25 cm. The perpendicular distance of the chord from the centre is:
In a circle with radius 5 cm, a chord is at a distance of 3 cm from the centre. The length of the chord is:
O is the centre of this circle. Tangent drawn from a point P, touches the circle at Q. If PQ = 24 cm and OQ = 10 cm, then what is the value of OP?