A key theorem in circle geometry states that the angle subtended by an arc at the center is double the angle subtended by it at any point on the remaining part of the circle (in the same segment).
Let the angle at the center be $\theta_{center}$ and the angle at the circumference be $\theta_{circumference}$.
The theorem can be expressed as:
$ \theta_{center} = 2 \times \theta_{circumference} $
We are given:
We need to find the angle subtended at a point on the circle in the same segment, $\theta_{circumference}$.
To find $\theta_{circumference}$, we can rearrange the formula:
$ \theta_{circumference} = \frac{\theta_{center}}{2} $
Substitute the given value:
$ \theta_{circumference} = \frac{60°}{2} $
$ \theta_{circumference} = 30° $
Thus, the angle subtended at a point on the circle in the same segment is 30°.
In a circle, a ten cm long chord is at a distance of 12 cm from the centre of the circle. The length of the diameter of the circle (in cm) is:
Chord AB of a circle of radius 10 cm is at a distance 8 cm from the centre O. If tangents drawn at A and B intersect at P., then the length of the tangent AP (in cm) is:
A chord 21 cm long is drawn in a circle of diameter 25 cm. The perpendicular distance of the chord from the centre is:
In a circle with radius 5 cm, a chord is at a distance of 3 cm from the centre. The length of the chord is:
O is the centre of this circle. Tangent drawn from a point P, touches the circle at Q. If PQ = 24 cm and OQ = 10 cm, then what is the value of OP?