The problem involves three concentric circles with radii in an arithmetic progression (AP).
Key Information:In an arithmetic progression, the difference between consecutive terms is constant. For three terms $a, b, c$, they are in AP if $b - a = c - b$. This simplifies to the property that the middle term ($b$) is the average of the first ($a$) and the third ($c$) term:
$ b = \frac{a + c}{2} $
Applying this property to the radii of the concentric circles ($r_1, r_2, r_3$):
The middle radius ($r_2$) is the average of the innermost radius ($r_1$) and the outermost radius ($r_3$).
$ r_2 = \frac{r_1 + r_3}{2} $
Substitute the given values:
$ r_2 = \frac{7 \text{ cm} + 21 \text{ cm}}{2} $
$ r_2 = \frac{28 \text{ cm}}{2} $
$ r_2 = 14 \text{ cm} $
The radius of the middle circle is 14 cm.
In a circle, a ten cm long chord is at a distance of 12 cm from the centre of the circle. The length of the diameter of the circle (in cm) is:
Chord AB of a circle of radius 10 cm is at a distance 8 cm from the centre O. If tangents drawn at A and B intersect at P., then the length of the tangent AP (in cm) is:
A chord 21 cm long is drawn in a circle of diameter 25 cm. The perpendicular distance of the chord from the centre is:
In a circle with radius 5 cm, a chord is at a distance of 3 cm from the centre. The length of the chord is:
O is the centre of this circle. Tangent drawn from a point P, touches the circle at Q. If PQ = 24 cm and OQ = 10 cm, then what is the value of OP?