The question relates to a fundamental theorem in circle geometry concerning the angles subtended by a chord (or arc).
The theorem states that the angle subtended by an arc at the center of a circle is double the angle subtended by the same arc at any point on the circumference (the remaining part of the circle).
Given:
To find the angle subtended by the same chord at any point on the remaining part of the circle, we use the theorem:
Angle at Circumference = $\frac{\text{Angle at Center}}{2}$
Calculation:
Angle at Circumference = $\frac{70^\circ}{2}$
Angle at Circumference = $35^\circ$
Therefore, the measure of the angle subtended by the same chord at any point on the remaining part of the circle is 35°.
In a circle, a ten cm long chord is at a distance of 12 cm from the centre of the circle. The length of the diameter of the circle (in cm) is:
Chord AB of a circle of radius 10 cm is at a distance 8 cm from the centre O. If tangents drawn at A and B intersect at P., then the length of the tangent AP (in cm) is:
A chord 21 cm long is drawn in a circle of diameter 25 cm. The perpendicular distance of the chord from the centre is:
In a circle with radius 5 cm, a chord is at a distance of 3 cm from the centre. The length of the chord is:
O is the centre of this circle. Tangent drawn from a point P, touches the circle at Q. If PQ = 24 cm and OQ = 10 cm, then what is the value of OP?