The question relates to a fundamental theorem in circle geometry concerning the angles subtended by a chord (or arc).
The theorem states that the angle subtended by an arc at the center of a circle is double the angle subtended by the same arc at any point on the circumference (the remaining part of the circle).
Given:
To find the angle subtended by the same chord at any point on the remaining part of the circle, we use the theorem:
Angle at Circumference = $\frac{\text{Angle at Center}}{2}$
Calculation:
Angle at Circumference = $\frac{70^\circ}{2}$
Angle at Circumference = $35^\circ$
Therefore, the measure of the angle subtended by the same chord at any point on the remaining part of the circle is 35°.
If a tangent to a circle from a point P meets the circle at A with AP = 15 cm. Given that the radius of the circle is 8 cm, find the distance of P from the centre of the circle.
In a circle with a radius of 10 cm. XY and PQ are two parallel chords 12 cm and 16 cm in length, respectively. The two chords are situated on the opposite sides of the centre. The distance between the chords is:
Find the equation of the tangents to the circle x2 + y2 = 9 at x = 2.
If a chord of length 24 cm is at a distance of 5 cm from centre, then find the radius of the circle.
Let \( C_1 \) and \( C_2 \) be two circles which do not externally touch and intersect each other and \( O_1 \), and \( O_2 \) be the centers of the circles, respectively. Let AB be the common transverse tangent to the circles such that P, Q are the points of tangency respectively to \( C_1 \), \( C_2 \). Let R be the point of intersection of \( O_1 O_2 \) and AB. If \( \angle PO_1R = 60^\circ \), find \( \angle QO_2R \) and \( \angle QRO_2 \) respectively.